The sinusoidal current i1(t) has a phase angle of 60 degrees. Furthermore, i2(t) attains its positive peak 0.25ms earlier than the current in i2(t) (i.e i1(t) leads i2(t)). Both currents have a frequency of 500 Hz. Determine the phase angle of i2(t)
I think we would use this equation: v1(t) = V1cos(wt + theta1)
The Attempt at a Solution
I just cant find a formula in t he book that adds both currents in order to obtain the missing phase angle. Much help is appreciated!