Sinusoidal current phase angle question

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SUMMARY

The discussion focuses on determining the phase angle of the sinusoidal current i2(t) given that i1(t) has a phase angle of 60 degrees and leads i2(t) by 0.25 ms at a frequency of 500 Hz. The period of the sinusoidal currents is calculated to be 2 ms, making 0.25 ms represent one-eighth of a full wave period. Consequently, the phase angle of i2(t) is determined to be 60 degrees minus 45 degrees, resulting in a phase angle of 15 degrees.

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Homework Statement



The sinusoidal current i1(t) has a phase angle of 60 degrees. Furthermore, i2(t) attains its positive peak 0.25ms earlier than the current in i2(t) (i.e i1(t) leads i2(t)). Both currents have a frequency of 500 Hz. Determine the phase angle of i2(t)


Homework Equations



I think we would use this equation: v1(t) = V1cos(wt + theta1)

The Attempt at a Solution



I just can't find a formula in t he book that adds both currents in order to obtain the missing phase angle. Much help is appreciated!
 
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You won't need a 'canned' formula for this problem. The first thing to determine is what fraction of a whole wave period does 0.25ms represent? What's the period of the sinusoids?
 

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