Recent content by Zacko282

THANKYOU

It opens down and the maximum value is 96

THANK GOD! Thanks a lot for the help, and how would i graph this parabola? Nvm found out how to graph it! now how do i find the max power?

i have, idk why i find this one so hard to understand =/ and ok so P = 24I - 1.5I^2 is the equation. How would i find the I intercepts to be able to find the axis of symmetry? (again thanks for helping me) (edit, would the vertex be (8,96))

No, the work document sent to me by the teacher doesn't even teach me how to solve this kind of question =/. and then does that mean for the equation in vertex form it would be y = 1.5 (x - 24) + 0 or (x - 0) + 24? I'm sorry I'm kind of slow =( This is the only problem all unit I've had...

Yes, i believe so, I find the x- intercepts of the equation and then use that to determine the a of the equation.

Do i simplify both sides of the equation and then isolate the variable ?

Ok, so The answer i get should be P = 22.5I then?

so the end equation would look something like this? P = I24 - I^2 1.5 ? or would it be P = I (24) - (1.5)^2 ? and for example if i put it into an equation of y = a (x - h)^2 + k would it be y = 24 (x - 0) + 1.5 ? Thanks for the help btw.

1. Determine the equation that represents the relationship between the power and the current when the electric potential difference is 24v and the resistance is 1.5 Ω. 2. Draw a graph of the parabola that corresponds to the equation found in (a). 3. Determine the current needed in order for...