Recent content by Zanket

Agreed. I said the tensile strength can be arbitrarily high, not infinite. It seems like you’re suggesting that the ability of the tidal force to break an object is unaffected by its tensile strength. But everything I’ve read says the opposite. I’m not sure I can prove that. But it doesn’t...

How is this different from saying that there’s no such thing as a freely falling object? Doesn’t this apply to even a dust particle? Even a dust particle is made up of interacting particles. You’re suggesting that any object floating in space rips apart due to forces other than tidal forces...

I don’t disagree with anything in your post. But how does it show the problem with my argument? The rod spans the horizon; the horizon is somewhere along the rod. When you’re grazing Alpha Centauri, its distance from you does not depend on your velocity; it’s zero. And you’re at Alpha Centauri...

Assuming for the sake of argument it implied that, how does it answer the key question: how can GR be self-consistent? More on this below. The rod I’m talking about is freely falling. By the definition of “freely falling object”, no forces except gravity are acting on the rod. Then if the rod...

For any part of the rod to fall inward through the horizon, the rod must first break. But that’s the question, whether or not the rod breaks. If you’re talking about one of the cloud of particles that forms the black hole, I don’t see why it would need to be close to a particle of the rod that...

Thanks so much for that great info pervect! But if MTW are right, then how is GR valid? Let a freely falling rod be escaping to r=infinity radially as it travels through a group of particles falling toward one another to eventually form a black hole, when a horizon forms along the rod so that...

I doubt this. Can you provide a reference please? What about for a freely falling observer who is just above the horizon and escaping to r=infinity (i.e. in free fall and moving away from the black hole)? Is the tidal force for such an observer independent of her velocity?

I spent a few years writing software to predict future price movements. It shows that stock price movements are predictable at least one day in advance, to a degree at which only a brokerage house could (greatly) profit. The transaction costs must be very small (like 0.05%) to profit. I didn't...

Disagreement with generally accepted viewpoints is not allowed here. If anyone wants polite discussion with me, email me by clicking on my alias on the paper, or google for an open-minded forum.

Nope. My text doesn't reference two clocks. Only one clock at a fixed position in the rocket is needed. The clock can be infinitesimally small. This thread can be locked now.

See post 79 and post 81. The coordinate system of an accelerated observer is immaterial here, because the observers (crew and observer on the planet) can measure the distance to the buoy (either passed in the case of the crew, or thrown up in the case of the observer on the planet) in an...

This is a non-issue. #3 talks about the distance the buoy recedes (one million proper light years) during time on the crew’s clock (ten proper years). The crew can always do a good measurement of their own clock. As I previously pointed out, they can do a good measurement of the distance to the...

The crew can shut down their engine at Andromeda, and then do the measuring. The relativistic rocket equations predict the measurements. It is given in #2 that they come to rest at Andromeda, so with their engine off there they’d remain at rest with respect to the buoy. Likewise the observer...

How small is “arbitrarily small”? If I give a different specific amount than you do, who is right? How small is “arbitrarily small” is an opinion. Then it’s clear that these definitions are not precise enough. To be unambiguous they need to say how you can determine how small the region must be...

The math has already been done, for #3 at http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html and, for #4, numerous sources about the cosmological horizon. It would be silly to duplicate that here.