Recent content by zebrastripes
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Z
Solving Motion along a Line: Finding Turning Points, Max U & Frequency
Thanks RGV, but under what assumptions can I say for small |x|? And would you mind giving me a hint about what to do for part 2)? Thanks again!- zebrastripes
- Post #3
- Forum: Introductory Physics Homework Help
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Z
Solving Motion along a Line: Finding Turning Points, Max U & Frequency
Homework Statement A particle P of unit mass moves along an x-axis under the influence of the force F(x)=2(x^{3}-x) Firstly, I find V(x)=x^{2}-x^{4}/2. Where equilibrium points are F(x)=0 so x=0 with energy V(0)=0, x=1 with energy V(1)=V(-1)=1/2. And I have also sketched the graph...- zebrastripes
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- Line Motion
- Replies: 2
- Forum: Introductory Physics Homework Help
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Z
Help Solving Calculus/Mechanics Question on Particle in Gravity Field
I'm really struggling to get my head around some of the mechanics applications in my calculus module and would really appreciate it if somebody could help me get my head around it. I have this question: A particle P of constant mass m has a position vector: r=x(t)i+y(t)j, and moves...- zebrastripes
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- Field Gravitational Gravitational field Particle Position Position vector Uniform Vector
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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IVP applications of second-order ODE
Ahh Ok, so it's my modulus work that's really poor! I'm thinking you're equation changes mine to: Aω/(ω^2-Ω^2)<H(ω+Ω) So with the substitution for A I get (ω-Ω)/(ω^2-Ω^2)<(ω+Ω) So from this, could I finish by showing this is true? Or have I gone wrong again? I'm thinking that my...- zebrastripes
- Post #3
- Forum: Calculus and Beyond Homework Help
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IVP applications of second-order ODE
Homework Statement Given the equation mx''+cx=cAsin(Ωt) with the initial conditions x(0)=0 and x'(0)=0. Solve the initial value problem for the case when Ω < ω and show that |x(t)| < H provided A < H(1-(Ω/ω)). Homework Equations The Attempt at a Solution For my solution to...- zebrastripes
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- Applications Ivp Ode
- Replies: 3
- Forum: Calculus and Beyond Homework Help