Recent content by zenity

Thanks... but this section in the book insists that we use integration by parts in order to solve these questions... (Although using substitution as a secondary method would be acceptable I think). I've solved the questions... but I'm now stuck on integration and trigonometric identities...

I'll need a quick refresher on that... I don't remember exactly how to do that... I'll take a look around on the net. In the meantime, I am 100% stuck on this question: integral of x^7/(1+x^4)^(3/2) I've tried assigning u=x^7 and dv="the bottom part" unfortunately... I don't know...

Ok... so this is what happens after I work it out u=ln(1+x)^2 du=2x/(x^2+1) dv=dx v=x ln(1+x^2)x - integral [ 2x^2/(1+x^2) Using a calc, I found out that the integral works out to be x - arctan(x) ... but I don't know how to do it ... any pointers?

Hi, I'm a bit confused as to what I should assign u and dv in this integration by parts: ln(1+x^2)dx I remember a general rule called the "LIPATE" rule... which is basically Logarithms, inverse trigs, poly, algebra, trig, then exponentials... Now... would I assign u = ln(1+x^2)? and...

mhmm if m=2... i got Xa = (2/3)H... is that right?

Ah... I think I understand what I just said. A'=B.. then you'd just have to sub it in. Man, boolean algebra is mighty weird! I just started a week ago, still getting the hang of it. Thanks for your help!

Mhm.. I understood all the steps until the last one...this is what I think... Since AB = 0 and A+B=1 That leaves us with two choices for A or B. A can either be 0 or 1, and B must be the exact compliment. Now we're stuck with C(A'+B). *Here's where I'm a bit confused* If A is 0, B...

Hi there, I've never done this type of Algebra... and it's a bit confusing. I've completed this question, but I don't know if I took the right steps... *=AND, +=OR, '=NOT If A*B = 0, A+B=1 Prove: (A+C)*(A'+B)*(B+C) = B*C I expanded it a bit and applied some of the rules. Can...

Was just wondering if there was a "shorter" method of solving this problem. nPr = 60. nPr = n!/(n-r)! n=? r=3 Works out to be n(n-1)(n-2) = 60. From here on, what different options do I have? I have several ways of solving it, but was wondering what would be the "easiest"...

I browsed through the Links button on the top, but I didn't see anything in the resources... I was wondering if anybody has good information / good practice questions on these topics? I understand some of the concepts... I just need to apply them! Thanks!

so the point would be... ( ln(3), 7-3ln(3) ) ? I'm just a bit confused graphically.

Oh, so I had to compute the derivatives for both slopes, then compare them? Interesting... thanks! I have to digest this info now.

I'm kinda stuck on this question... my text gives me a simple example, but it's far from enlightening. Just wondered if I could get some help! "At what point on the curve y = 1 + 2e^x - 3x is the tangent line parallel to the line 3x -y =5?" Would I just need to simply compare the slopes...