Recent content by ZenSerpent

Actually Sir, I intend to formulate a mathematical expression for the efficiency of the transformer that is explicitly expressed in terms of N1, N2, r2 (outer radius of the toroidal core), and h (height of the cross-sectional area, probably I may even assume a square cross-sectional area to make...

Alright, I get it. When we expanded the complex numbers into the real and imaginary part, we disregarded the negative sign in computing for its arg( ) but we promised to put the negative sign in sin(wt - arg(z)). So generally speaking, it's just |z| sin(wt + arg(z)) if we included the negative...

Got it. But I now have this question. Notice that arg(z) is already negative. That means the general form should be i2(t) = V1max*|z|*sin(wt + arg(z))? Not i2(t) = V1max*|z|*sin(wt - arg(z)) for those circuits that involve inductance?

Sir Electrician. There is still a problem. I applied what you did in Mathematica using the expressions for the transformer. Attached are photos for the phasor one and the other one for the Laplace. I scaled both 10000x. It turns out that they don't look identical.

Yes, I am. Well, I think things will get a little bit more complex if I dig deeper into the losses. After all, the point of our thesis, is to simply apply mathematics in real-situations. Relating the electrical parameters in the previous thread has already applied enough of the serious and...

Homework Statement To set-up an equation for the efficiency equation of single-phase toroidal transformer given the circuit with the following mesh equations (s*L1+R1)*I1 + (-s*M)*I2 = V1 (-s*M)*I1 + (s*L2+R2+RL)*I2 = 0 Homework Equations Efficiency equation(?), equation derived by The...

That's what I'm trying to say several posts ago. Woah! Thank you so much The Electrician and rude man.

So the bottom line of all these is that we cannot see V1max in the function of i2(t) = |z| sin(wt - arg(z)) but the unit of sin(wt - arg(z)) is in volts since there will be a hidden 1 volt in there regardless of what the value of V1max is, right? (Even if V1max is not equal to 1.)

What if the initial amplitude is v1 max =/= 1. Will I not be able to see its value in the expression in i2(t). I apologize as this still confuses me up to now.

So instead of i2(t) = |z| sin(wt - arg(z)) It needs to be i2(t) = V1max*|z| sin(wt - arg(z)) Or I'll just have to consider i2(t) = |z| sin(wt - arg(z)) with sin(wt -arg(z)) having a unit of volts?

Well this sounds counter-intuitive to me as, v1max is in volts and sin wt is dimensionless. So the amplitude of the input sine wave, which is v1 max doesn't really matter at all in the i2(t)?

The Electrician, so the expression I mentioned in #29 is correct right? One thing I noticed is that all the units cancel out. Why is this?

Sir rude man, yup, failure to perform convolution is a serious mistake. But if I were to perform convolution, I'll get an expression as hairy as the one posted by The Electrician in the post above. So, I think phasor analysis is the way to go. And I now gained some good insight just now. And I...

Oh my! So the best option is phasor analysis. Using that on z = I2(s)/V1(s) the time domain function is i2(t) = |z| sin(wt - arg(z)) right?

Correct me if my understanding of this is wrong. So using this circuit, you determined the output to input ratio as R/(R + sL). Now since, this is Vo(s)/Vi(s), you wanted to obtain the function for vo(t), given that vi(t) = sin(wt). So what you basically did was you took the LT of vi(t) so that...