# Setting up the Transformer Efficiency as Objective Function

• ZenSerpent
In summary: L1, L2 (lengths of...). The objective function will be to find the transformer efficiency at a particular set of values for those parameters.In summary, the efficiency of a transformer can be maximized when the losses on the primary and secondary are equal.
ZenSerpent

## Homework Statement

To set-up an equation for the efficiency equation of single-phase toroidal transformer given the circuit with the following mesh equations

(s*L1+R1)*I1 + (-s*M)*I2 = V1
(-s*M)*I1 + (s*L2+R2+RL)*I2 = 0

## Homework Equations

Efficiency equation(?), equation derived by The Electrician at thread https://www.physicsforums.com/threa...-parameter-i2-to-v1-non-ideal-updated.901475/.

## The Attempt at a Solution

We're not sure about this but is it not V2*I2*cos(theta2)/(V1*I1*cos(theta1)) or M*di2/dt*cos(theta2)/(V1*I1*cos(theta1))? Or should I include the hysteresis and eddy current losses?

P.S. We're Applied Mathematics students, not EE, however we actually needed these for our research. Thanks in advance.

I assume you are a university student; is this the case?

You should visit your library and consult the Transactions of the IEEE on Magnetics. You can probably find a lot of information there about modeling losses in magnetics. The IEEE publications are available online at http://ieeexplore.ieee.org/Xplore/home.jsp. Usually a university library will give you free access.

Yes, I am.

Well, I think things will get a little bit more complex if I dig deeper into the losses. After all, the point of our thesis, is to simply apply mathematics in real-situations. Relating the electrical parameters in the previous thread has already applied enough of the serious and beautiful maths concepts. How about if I'll just assume the losses to be a portion of power? On your experience Sir, how much of the power (in %) is the combined value of the hysteresis and eddy current losses?

It is known that the optimum design (for continuous full power operation) for a transformer is to make the copper losses the same as the iron losses. The copper losses are the power loss due to the resistance of the copper wires used to make the primary and secondary windings. Those losses vary somewhat with temperature.

The iron losses are mostly the hysteresis and eddy current losses.

The optimum design where copper and iron losses are equal only applies when the transformer is operated at full power continuously, which is often not the case. If the transformer is not operated at full power continuously, the design for optimum becomes more difficult.

A typical medium size to large size transformer will be on the order of 98% efficient, with copper and iron losses similar in value.

You would be solving a problem close to real life if you chose your values for R1, R2 and RL so that the losses in R1 and R2 together are, say, 5% of the power in RL. Also, make the loss in R1 about the same as the loss in R2.

The iron losses are almost invariant with the load on the transformer, so if you want to get more realistic you could add a third resistor, R3, to represent the combined iron losses. Connect R3 in parallel with the primary winding. This way, the loss in R3 will not increase when the power supplied to RL increases. Consult the "Real transformer equivalent circuit" here: https://en.wikipedia.org/wiki/Transformer. You would choose the value of R3 so that the loss in R3 is about the same as the loss in R1 and R2 at full load.

By the way, if you do choose to add another resistor R3 in parallel with the primary, don't be surprised when your expressions from both the phasor solution and the Laplace solution exhibit a fairly large increase in complexity. This phenomenon is the bane of Electrical Engineers. The very large expressions that occur when just a few more components are added to a circuit are called "high entropy" expressions. Before software like Mathematica became available, symbolic expressions were not derived. EEs learned how to make good approximations for real life circuits.

As I read your title for this thread, "Setting up the transformer efficiency as objective function", I'm wondering if you are hoping to come with a mathematical expression for the efficiency of the transformer, and further hoping that that function will have a maximum value as you vary certain transformer parameters? As your circuit stands now, its efficiency will vary with the values of R1, R2 and RL, but the maximum efficiency will occur when R1 and R2 are zero, not a very interesting outcome.

The Electrician said:
As I read your title for this thread, "Setting up the transformer efficiency as objective function", I'm wondering if you are hoping to come with a mathematical expression for the efficiency of the transformer, and further hoping that that function will have a maximum value as you vary certain transformer parameters? As your circuit stands now, its efficiency will vary with the values of R1, R2 and RL, but the maximum efficiency will occur when R1 and R2 are zero, not a very interesting outcome.
Actually Sir, I intend to formulate a mathematical expression for the efficiency of the transformer that is explicitly expressed in terms of N1, N2, r2 (outer radius of the toroidal core), and h (height of the cross-sectional area, probably I may even assume a square cross-sectional area to make things simpler, so it may be just r2 - r1). Assuming the case of a step down transformer and the secondary winding will simply be coiled on top of the primary coil instead of placing it on the side of the secondary coil, we will know that Circumference of the Inner Circle of the Core = 2*pi*r1 = N1*d1, where r1 = radius of the inner circle and d1 = diameter of primary winding wire. Solving for r1, we get r1 = N1*d1/(2*pi), thus making r1 dependent to one of the parameters. The diameters of the wires will just be constant as the one who intends to design a certain transformer will just specify it. All the lengths of the wires and the cross sectional area of the core will be explicitly expressed in terms of the four parameters. As for the case of using the derived expression in the previous thread, I'll relate all the v's and i's to i2 and v1. After which I'll take the partial derivatives of the functions in terms of the four parameters, equate all of them to 0 and solve the system of equation for the values of the four parameters (Fingers crossed that Mathematica will be able to do these, and I do hope that v1 and i2 will not be canceled out). These values will be the optimal N1, N2, r2, and h, given v1, i2, and the properties of the wire and core used, as per the application of multivariable optimization in calculus. Can you imagine what my plan looks like, Sir?

You should have a look at these:

https://en.wikipedia.org/wiki/Steinmetz's_equation

https://en.wikibooks.org/wiki/Electronics/Transformer_Design

When using a given core, whether standard EI laminations, or a toroid, there is a winding window through which the turns of the winding must pass. The idea is to get as much wire through that window as possible. The area of the window is filled with wire, but since the cross section of the wire is round, there will be some wasted space. The ratio of the cross sectional area occupied by all the wire comprising the windings, to the window area is called the fill factor. If you change the number of turns in a winding, you must also change the wire diameter so that the fill factor is as large as possible.

The voltage applied to the primary winding will be fixed. This means that as you change the number of turns, the flux density in the core will change, and that will change the core loss.

So when you make the wire diameter larger, and thus that winding will have fewer turns, the resistance of that winding will decrease, BUT the flux density will go up, so the core loss will increase.

This is the major trade off in transformer design. Fewer turns of bigger wire means less copper loss, but more core loss. You have to find the balance between those two giving minimum total loss, and therefore maximum efficiency.

Last edited:

## 1. What is the objective function in setting up transformer efficiency?

The objective function in setting up transformer efficiency is a mathematical representation of the desired outcome or goal in optimizing the efficiency of a transformer. It is a function that takes in different parameters, such as input voltage, output voltage, and current, and calculates the overall efficiency of the transformer. The goal is to minimize this function, as a lower value indicates a more efficient transformer.

## 2. How is the objective function used to optimize transformer efficiency?

The objective function is used in conjunction with optimization algorithms, such as gradient descent or genetic algorithms, to find the optimal values for the transformer's parameters. The algorithm iteratively adjusts the parameters and calculates the efficiency using the objective function until it reaches the minimum value, indicating the most efficient set of parameters for the transformer.

## 3. What are the parameters used in the objective function for transformer efficiency?

The parameters used in the objective function for transformer efficiency may vary depending on the specific transformer and its design. However, some common parameters include input voltage, output voltage, current, and resistance. Other factors such as core material, winding design, and load conditions may also be considered in the objective function.

## 4. Can the objective function be adapted for different types of transformers?

Yes, the objective function can be adapted for different types of transformers by adjusting the parameters and equations used in the function. For example, a transformer used in power transmission may have different parameters and equations compared to a transformer used in electronics. Therefore, the objective function must be customized accordingly to optimize the efficiency for each type of transformer.

## 5. How important is optimizing transformer efficiency using the objective function?

Optimizing transformer efficiency using the objective function is essential in reducing energy waste and improving the overall performance of the transformer. A more efficient transformer results in lower operating costs and reduces the environmental impact. Therefore, it is crucial to continuously strive for optimal efficiency by utilizing the objective function in transformer design and maintenance.

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