Recent content by ZephyrWest

Yes, so if I was in one of the rockets, I would see the other moving traveling away away from me at 0.976c. The external observer on the ground would see the two rockets traveling away from each other at 1.6c. This is possible because special relativity permits two separate objects to have a...

Hmmm... ok. From the frame of reference of one of the spacecraft s, is the separation rate, or speed, this? \frac{0.80c + 0.80c}{1 + \frac{(0.80c)(0.80c)}{c^2}} = \frac{1.60c}{1.64} = 0.976c And, what is "contradiction SR"?

I understand relativistic velocity addition but am not sure how to apply it to this situation. Can you please explain?

Here's the problem: I know that nothing can exceed the speed of light c. So is it consistent with special relativity because it is not a physical object that is moving at 1.60c? I'm asking because I'm really not sure if I'm correct. Thanks for your help.