Recent content by Zeus5966

For pre-cal? I'm in first year calculus for engineers! I must say I do actually find calculus more interesting than precalculus, as crazy as it sounds.

One of those "why" questions, as it seems to me needs some sophisticated knowledge about integration, which I don't have yet. That comes next semester :)

I just realized I answered my own question in my question. Thank you for the help Simon

Apparantly the computer can't tell the difference between 488.48 and 488.5. I was trying to figure out what I was doing wrong, just a fussy website. As it stands, after reading the question four times, the reason they say about the z-axis, to my understanding is that the disk is rotating around...

I did sketch it out, however it still makes no sense due to the confusing directions. I'm not quite sure what you mean by Fperpendicular. How would I find that? And why would there be a difference? The force, to my understanding is already tangent to the disk at force 1 judging by the wording...

The equation (Vf+Vi)/2 * t is derived from the kinematics equation s = s0 + vi*t + (1/2)*a*t2. We know that a = Δv/Δt, so we can substitue it into a in the initial kinematics equation. s0 is 0 if we're starting from the origin(let's assume we are) and ti starts from 0) so that gives us s = vit...

What you want to do is try using the conservation of energy theorem: Ki + Pi = Kf + Pf It starts from rest so Ki = 0, we want to find hf, which is in Pf, so solve for that In the end your equations should work out to be m*g*hi - (1/2) * m *vf2 = mghf Use algebra to solve for hf. You can see...

Homework Statement A uniform disk with mass m = 9.27 kg and radius R = 1.42 m lies in the x-y plane and centered at the origin. Three forces act in the +y-direction on the disk: 1) a force 344 N at the edge of the disk on the +x-axis, 2) a force 344 N at the edge of the disk on the –y-axis...

This is the third time I've attempted to post this today... Not sure if it's getting through or not, but I was on a mobile device, maybe it didn't go through. Anyway, is Ue in fact the gravitational potential energy in terms of the radius of the Earth only, and Um is the gravitational potential...

Homework Statement Part 1(complete and correct. I'm including this for context's sake) You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the Earth with enough speed to make it to the moon. You leave the surface of the...