What is the Height at Which a Falling Ball Reaches a Velocity of 5.2 m/s?

AI Thread Summary
A ball falling from an initial height of 5 meters is analyzed to determine the height at which it reaches a velocity of 5.2 m/s. The conservation of energy theorem is applied, leading to the equation m*g*hi - (1/2) * m * vf^2 = mghf. Since mass cancels out, the solution can be derived without needing the mass value. The final height is calculated successfully using algebra. The approach confirms that energy conservation principles effectively solve the problem.
maddief
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Homework Statement


A ball falls from rest from an initial height of 5m above the ground. At what height above ground level will the ball be moving at 5.2 m/s?

Homework Equations


gravitational energy = mgh
kenetic energy=(1/2)mv^2

The Attempt at a Solution


I tried solving for both types of energy but I do not have mass so I am not sure how to solve. Please help!
 
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What you want to do is try using the conservation of energy theorem:
Ki + Pi = Kf + Pf
It starts from rest so Ki = 0, we want to find hf, which is in Pf, so solve for that

In the end your equations should work out to be
m*g*hi - (1/2) * m *vf2 = mghf
Use algebra to solve for hf. You can see that all the masses cancel, so you don't need them, and the velocity you have is vf! Let me know if it works.
 
Thank you! It worked!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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