Recent content by Zhang Jiawen

a<b, a^b=b^a, how to solve such kind of equation?

I knew that a polynomial of degree n has n+1 basis, i.e 1,x,x^2...x^n; But what if a0=0,i.e the constant term is 0, like x^3+x, then what is the dimension and the basis? Is there only x(one dimension) as the basis?

It is known that f"x>0,f(x)=f(-x),then which is correct? f(0)<f(1); f(4)-f(3)<f(6)-f(5); f(-2)<(f(-3)+f(-1))/2 Can I simply use y=x^2 to conclude that only the third is incorrect? Thx!

Let f be a function on [0,major infinity] such that for each point in its graph,(x,y)=(y*y,y).At how many points must each point in f have a limit...?I'm not clear what the question is aiming...