Recent content by ziptrickhead

This is just like your other question with the pressure and volume. Once again, this requires NO calculus at all (except maybe some theory). Normally you could divide the circle into an upper and lower hemisphere. Intergrate to find the area under the 2 hemispheres and take the difference to...

Is that an equation from a textbook? Don't think about trying to apply an equation. Instead, use theory and some common sense. You state in the problem that there is a figure that you don't show. It does sound like you have a pressure vs volume plot where there is a straight line from p1,V1 to...

Homework Statement When a star like our Sun no longer has any hydrogen or helium "fuel" for thermonuclear reactions in its core, it can collapse and become a white dwarf star. Often the star will "blow off" its outer layers and lose some mass before it collapses into the rapidly spinning...

Ohhh, so since the board is basically on each surface the same amount of time, the force of friction would be the average of the force of friction for each separate surface: F_f1=Mg(mu_1) F_f2=Mg(mu_2) => (F_f1+F_f2)/2 = Mg(mu_1+mu_2)/2

So basically because the board is uniform, the normal force is uniform. So if i were to divide the board into 2 separate boards then the value of the normal force would also be divided into 2? So since there are two different surfaces, it would be dividing the force by two eg...

A uniform board of length L and mass M lies near a boundary that separates two regions. In region 1, the coefficient of kinetic friction between the board and the surface is mu_1, and in region 2, the coefficient is mu_2. Find the net work W done by friction in pulling the board directly from...

I'm working on this problem for homework. Basically it's to find the work done by friction. Now for the work it would be the force of friction times the displacement. The problem is the board being pushed is going over 2 different surfaces, with 2 different values for friction, at the same time...

Your weight is your mass times gravity. So if you want to find out your mass play around with Newton's second law.

Thank you very much! I see what I was doing wrong now. I didn't even understand how one pulley works let alone try to figure out 2 pulleys.

If tension equals F then: F=3T so tension would equal F/3. So then the force required to pull the man up would be Mg/3. I think I'm starting to understand, just that the Tension=Force part I was missing.

Well, 3 ropes would stick out. Obviously I'm thinking in the wrong direction because i tried Mg/6 and it said I was off by a multiplicative factor. I checked online and saw a picture of a 2 pulley system that showed that the tension of each rope would be 1/2T. If I were to add up the tension...

Well, you would have the force pulling on the platform from the first pulley and then tension from the bracket so the rope would pull twice on the platform/man? That would go with the feedback statement and because there are 2 forces pulling the platform/man then the force required would be...

I have this problem for homework. Find the magnitude of the minimum force F that allows the window washer to move upward. Express your answer in terms of the mass M and the magnitude of the acceleration due to gravity g. The professor didn't go over multiple pulleys though so I am...