Seems that v+ can not be equal to v- in the ideal condition; or the non-ideal condition. But I can not figure out what will happen in the circuit; Can you give more hints on that? Thank you!
Oh!!! So the time constant is decided by the equal circuit of Rt in series with C? So time constant \tao = Rt* C = 10k * 100m = 1000 ???!!! I need to go back to learn how I can derive that "( R1 // R2 ) = Rt, the Thevenin resistance at Vt." Thanks Baluncore and Dave!
hi Baluncore, I didn’t...
Hi all, I attached my attempt at a solution in the attached picture. I am using the textbook titiled as ”electronic circuit analysis“ by David E. Johnson, and op amp is in chap 3;
while I did not find any example that attach the Vee and Vcc with amplifier . It seems that v+ = v- doesn’t hold in...
Oh!!! So the time constant is decided by the equal circuit of Rt in series with C? So time constant \tao = Rt* C = 10k * 100m = 1000 ???!!! I need to go back to learn how I can derive that "( R1 // R2 ) = Rt, the Thevenin resistance at Vt." Thanks, Baluncore and Dave!
Got it! So until the capacitor is charged to Vt, the transistor is off, which means I just analyze the circuit in which R1 and (R2//C) are in series. Now I guess I know how to solve it. Thanks much!