Recent content by zuN

The professor gave me the value for seawater as 1025 kg/m^3.

so if i omit the atmospheric pressure then it'll be p = 1.025(10^3)(9.8)(d) now p = F/A = 1.10(10^6) / (pie)(0.04) = 8.75(10^6) Pa. 8.75(10^6) / 1.025(10^3)(9.8) = d d = 871m. answer was 868. thanks for the help Phanthom Jay

Hi i need some help with a problem: A submarine has a 40.0cm diameter window 8.50cm thick. The window can withstand forces up to 1.10x106 N. What is the submarine's maximum safe depth? The pressure is maintained at 1.0atm and it's in salt water. Salt water density = 1025 kg/m3. the...