Recent content by zx95

1. In the system shown in the figure, the pulleys on the left and right are fixed, but the pulley in the center can move left or right. The two hanging masses are identical, and the pulleys and ropes are all massless. Find the upward acceleration of the mass on the left, in terms of g. 2. I have...

He had us do a problem yesterday with the techniques he'd like us to use for this problem I think. He wanted us to show that acceleration = -g. We did this like this: dv/dt = (dv/dK)(dK/dU)(dU/dy)(dy/dt) a = (1/mv) (-1) (mg) (v) a = -g Using this system, I came up with: a =...

My professor started the semester with Conservation of energy, and I've heard from other students that's not the way most classes go. With that in mind, we have yet to encounter any equation that looks like F = ma or tension. Or force at all for that matter. Thanks for the links, I'm going to...

Thank you very much! I always make mistakes like that. I need to work on that. Thanks!

1. There's a pulley with a larger mass (m1) on one side, and a smaller mass (m2) on the other side. What is the magnitude of acceleration of the masses? 2. I think this is going to use conservation of energy equations: U = mgy and K = (1/2)mv^2 3. I began by setting up these equations: D =...

Thank you for the quick response! I took this information and came up with the following: t1 = sqrt(2X1/g) t2 = sqrt(2X2/g) T = t2 - t1 T = sqrt(2X2/g) - sqrt (2X1/g) T = sqrt(2(X2-X1)/g) sqrt(g) = sqrt(2(X2-X1))/T g = 2(X2-X1)/T^2 I plugged this into the professors software...

1. Two steel balls are suspended from electromagnets, and are released simultaneously when the electric current is shut off. They start at heights X1 and X2, with X2 being higher. When they hit the ground, they land T seconds apart. Find an equation for g (the gravitational field) in terms of T...