Recent content by zygisyyy

thanks. now i know how to solve this equation

Homework Statement A thin tube, sealed at both ends, is 1 m long. It lies horizontally, the middle 10 cm containing mercury at the two equal ends containing air at standard atmospheric pressure. If the tube is now turned to a vertical position, by what amount will the mercury be displaced...

Q + A = delta U

so i should use U=3/2*m/M*R*T? or calculate as the sum of potential and kinetic energies? But i don't know the formula for the potential energy of monatomic and diatomic gases

Hi, I thought maybe equation pV=nRT may work, but when i tried entering the values into the equation the answer was wrong ( near the proplem there are answers 1350 K for monatomic gas and 730 K for diatomic ). Then I tried surfing the web and found that the dimensionless specific heat capacity...

a monatomic ideal gas initially at 17°C is suddenly compressed to one-tenth its original volume. What is the tmeperature after copression? make the same calculations for a diatomic gas.