Pressure difference between two points in a tapered pipe

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Homework Help Overview

The discussion revolves around determining the pressure difference between two points in a tapered pipe, specifically addressing the implications of fluid height and pressure relationships in the context of fluid mechanics.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive an equation for the pressure difference but expresses uncertainty about potential errors in reasoning or algebra. Some participants question the sign of the height difference and its implications on pressure, while others suggest revisiting the algebraic relationships involved.

Discussion Status

Participants are actively engaging with the original poster's reasoning, pointing out possible algebraic errors and questioning assumptions about pressure and height. There is a focus on clarifying the relationships between pressure, height, and fluid dynamics, with hints being offered for further exploration.

Contextual Notes

There are indications of confusion regarding the effects of fluid velocities at the two points and the role of atmospheric pressure in the equations presented. The discussion reflects a need for deeper examination of the underlying principles of fluid mechanics.

I_Try_Math
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Homework Statement
The pipe in the figure is transporting oil (density 850 kg/m3). The velocity at point 1
is 0.5m/s, but at point 2 it is 1.0m/s. Calculate the difference in height in the two open thin tubes
Relevant Equations
Bernoulli's equation
Trying to find an equation for the pressure difference between point 1 and 2. Not sure if my overall reasoning is incorrect, or I introduced a sign error somehow. The equation I come up with implies that the difference is a negative number, but that can't be true if the area of pipe at point 1 is larger than it is at point 2, as it in the given diagram?

Here's my work:

## l_1 ## and ## l_2 ## are intended to mean the distance from points 1 and 2 to where the fluid meets the air.

## P_1 + \rho g l_1 = P_{atm} ##

## P_2 + \rho g l_2 = P_{atm} ##

## P_1 + \rho g l_1 = P_2 + \rho g l_2 ##

## P_1 - P_2 + \rho g l_1 = \rho g l_2 ##

## P_1 - P_2 = \rho g l_2 - \rho g l_1 ##

## P_1 - P_2 = \rho g(l_2 - l_1) ##

## P_1 - P_2 = \rho g(-h) ##
 

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The height difference should not have any sign.
The lesser height reached by its liquid column is the effect caused by the lower internal static pressure in cross-section 2.
 
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Lnewqban said:
The height difference should not have any sign.
You are missing the point. There is an error in the algebra.
I_Try_Math said:
## P_1 + \rho g l_1 = P_{atm} ##
Think about that again.
 
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haruspex said:
You are missing the point. There is an error in the algebra.

Think about that again.
I still can't tell what is incorrect about the equation relating ## l_1 ##, ## P_1 ##, and ## P_{atm} ##. Any hints are appreciated.
 
I_Try_Math said:
Any hints are appreciated.
Look at some limit cases.....what if atmospheric pressure is nil......does your equation for P1 seem correct? What if it gets bigger than 0?
 
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I_Try_Math said:
I still can't tell what is incorrect about the equation relating ## l_1 ##, ## P_1 ##, and ## P_{atm} ##. Any hints are appreciated.
If you are normally swimming, your ears feel atmospheric pressure only.
If you then are diving at a depth of 10 meter under the surface of the sea, your ears are feeling the pressure exerted by the column of water above you plus the pressure exerted by the atmosphere.
 
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Are you saying that there is no effect of the fluid velocities at the two points?
 
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