A homemade mechanics problem: A beetle on a globe

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SUMMARY

The discussion analyzes the rotation of a homogeneous sphere of radius R with moment of inertia J, about its fixed center O, caused by a beetle of mass m crawling along a circular trajectory of radius b on the sphere's surface. The key conclusion is that the sphere rotates by a specific angle given by the formula 2π(1 - √(1 - (mb²(2J + mR²)) / (J + mR²)²)) when the beetle completes one full circuit. The rotation axis passes through the sphere's center and the center of the beetle's circular path, and the problem reduces effectively to two dimensions due to the absence of lateral forces and gravity. The beetle's path does not need to be a great circle, but the sphere's rotation axis and angular momentum conservation dictate the final rotation angle.

PREREQUISITES

  • Rigid body dynamics with fixed point rotation
  • Moment of inertia calculations for spheres (J and related formulas)
  • Angular momentum conservation principles in multi-body systems
  • Differential equations describing rotational motion of coupled systems

NEXT STEPS

  • Numerical integration of the derived system of ordinary differential equations (ODEs) for the ball-beetle system
  • Study of rotation axes determination for rigid bodies with internal moving masses
  • Analysis of angular velocity vector evolution in body-fixed and inertial frames
  • Investigation of non-great circle trajectories and their impact on sphere rotation

USEFUL FOR

Physicists and mechanical engineers studying rigid body dynamics, researchers modeling coupled rotational systems with internal moving masses, and neurophysiologists using spherical treadmills for insect locomotion experiments will benefit from this discussion. It provides a rigorous analytical framework and closed-form solutions for rotation induced by internal mass movement on a fixed sphere.

  • #31
Yes and It is not a surprise. If ##b = 0##, then the beetle is at rest, and thus the ball does not move. If, in the theorem cited in #29, the initial position coincides with the final position, then the axis of rotation is not defined uniquely .
 
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  • #32
As an example, for b=R/2, this vector is
$$(\sqrt{3},0,1)^T=2* ( \frac{\sqrt{3}}{2}, 0 , \frac{1}{2} )^T$$
I would like to understand how this (x,0,z) type vector of magnitude ##\frac{R}{b}## tells us about the final angle position of the ball.
 
Last edited:
  • #33
Once again: this vector is the direction vector of the ball's rotation axis. The magnitude of this vector does not matter. The angle of rotation about this axis is given in #27.
 

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