Understanding the f(t) Function of a Graph

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SUMMARY

The function represented by the graph is not accurately described by f(t) = u[sin(pi*t)]. The amplitude of the sine wave is approximately 1.3, not 1.0, indicating a need for adjustment in the function representation. To accurately depict the graph, one should create a series of u(t) pulses shifted by 2 units and multiply this series by 1.3sin(pi*t). Furthermore, the graph does not satisfy the definition of a function, as it does not provide a unique y-value for every x-value.

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MylordGoblin
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can somebody tell me wath the function of this graph is ?

http://studweb.hogent.be/~023112kv/graph.JPG"

Is this correct ?

f(t) = u [ sin (pi*t) ]



thx
 
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MylordGoblin said:
Is this correct ?

f(t) = u [ sin (pi*t) ]

thx
I don't think so. First of all, the amplitude of the sine looks to be about 1.3, not 1.0. And the graph shows both a series of a time-shifted u(t) pulses and the result of multiplying that pulse train time the 1.3sin() waveform.

If you want to represent the sine part of the graph, make a series of u(t) pulses shifted by 2 each time, and multiply that series times 1.3sin(). That should get you closer.
 
Maybe this doesn't answer your question, but i don't think this is a function see the first property of a function is that there is one and only one value of y for every value of x
can you tell me what does f(0.9) equal ?
is it near zero like the sine wave says or is it 1 like the square waves show...
 

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