Aether
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No.clj4 said:You are inverting (8b), right?
I would expect to see a term in [tex]\omega_{pq}[/tex] in (8c). I am not seeing it.
[tex]\omega_{pq}=[p^2\pi^2\epsilon \mu \frac{c_0^2}{a_0^2}+q^2\pi^2\epsilon \mu \frac{c_0^2}{b_0^2}]^{1/2}[/tex] Eq. (8b),
with [tex](p,q)=(1,0)[/tex], and [tex]\epsilon \mu =1[/tex]:
[tex]\omega_{10}=\pi \frac{c_0}{a_0}[/tex].
[tex]\omega_{10}[/tex] is a cutoff angular frequency in the absolute frame, and [tex]\omega_c[/tex] is that cutoff angular frequency in a moving frame:
[tex]\omega_c=\frac{\pi c_0}{a}[/tex].
To transform [tex]\omega_{10}[/tex] to [tex]\omega_c[/tex] using Eq. (1) we need to suppose that [tex]a_0[/tex] is a distance along the x-axis, and absolute motion is along the x-axis (this is necessary for now because Eq. (1) can only be used for motion and distance along the x-axis):Could you show the steps, at a superficial view, if I look at (8b) and at (1), i would expect to see the exponent [tex]{-1/2}[/tex] in (8c)
[tex]\omega_{c+}=\frac{\pi c_0}{\gamma (a_0-vt_0)}[/tex].
However, [tex]a_0[/tex] lays along the x-axis while the wave propagates along the z-axis, and E reciprocates in the [tex]\pm x[/tex]-direction. So, this last equation only applies while the transverse wave motion is in the [tex]+x[/tex] direction; while the transverse wave motion is in the [tex]-x[/tex] direction this equation applies:
[tex]\omega_{c-}=\frac{\pi c_0}{\gamma (a_0+vt_0)}[/tex].
Eq. (8c) is an attempt to compute the average of these two equations, and may change slightly if this average turns out not to be done quite right.
[tex]\omega_c=\frac{2\pi c_0}{\gamma((a_0-vt_0)+(a_0+vt_0))}=\frac{\pi c_0}{\gamma a_0}[/tex];
[tex]\omega_c=\frac{2\pi c_0}{(a_0-vt_0)+(a_0+vt_0)}[1-\frac{v_x^2}{c_0^2}]^{1/2}=\frac{\pi c_0}{a_0}[1-\frac{v_x^2}{c_0^2}]^{1/2}[/tex] Eq. (8c);
[tex]\omega_c=\frac{2\pi c_0}{(a_0-vt_0)+(a_0+vt_0)}[1-\frac{v_x^2}{c_0^2}]^{1/2}=\frac{\pi c_0}{a_0}[1-\frac{v_x^2}{c_0^2}]^{1/2}[/tex] Eq. (8c);
[tex]a_0[/tex] and [tex]b_0[/tex] are the dimensions (in the absolute frame) of the interior cross-section of the waveguide. [tex]a_0[/tex] is taken to be along the x-axis, [tex]b_0[/tex] is taken to be along the y-axis. The electromagnetic wave propagates longitudinally along the z-axis. In a moving frame, these two dimensions transform to [tex]a[/tex] and [tex]b[/tex] respectively.Who are a0 and b0?
It is possible to compute [tex]\omega_c[/tex] and [tex]k[/tex] for a waveguide in a moving frame simply by transforming these coordinates (a,b).
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