Simple Integral but unknown method

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    Integral Method
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SUMMARY

The discussion centers on solving the equation x + 1/(x + 2)(x + 3) = A/(x + 2) + B/(x + 3) to find the constants A and B. The user successfully derived the right-hand side as {A(x + 3) + B(x + 2)}/{(x + 2)(x + 3)}. This led to the system of equations A + B = 1 and 3A + 2B = 1, which can be solved to determine the values of A and B definitively.

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x+1/(x+2)(x+3) = A/x+2 +B/x+3

how do u calculate A and B ?

nevermind i got it thanks.
 
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R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}

Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1
 

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