Will There Be Liquid Water or Steam in the Cylinder at 0.5 ATM and 99°C?

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Discussion Overview

The discussion revolves around the state of water and an imaginary immiscible substance in a pressurized cylinder at a specific temperature and pressure. Participants explore the implications of partial pressures and the conditions under which each substance exists, considering both theoretical and hypothetical scenarios.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant proposes a two-component system with water and an immiscible substance, questioning whether liquid water or steam will be present at 1 atm and 99°C.
  • Another participant suggests that at 0.5 atm and 99°C, pure liquid water would exist in a vapor phase, specifically as superheated steam.
  • There is a discussion about whether water should be treated under 1 atm or 0.5 atm conditions due to the presence of the immiscible substance and its impact on partial pressures.
  • Participants explore the thermodynamic properties of the immiscible substance, noting that at 0.5 atm and 99°C, it would also be in a gas phase, while at 1 atm it would be liquid.
  • A later reply indicates that both substances would be in a gas phase at 0.5 atm and 99°C, despite the cylinder being set to 1 atm, due to their partial pressures.
  • One participant mentions that the saturation temperature corresponding to a saturation vapor pressure of 0.5 atm for both substances would be 82°C.

Areas of Agreement / Disagreement

Participants generally agree that both fluids will be in a gas phase at 0.5 atm and 99°C, but there is ongoing exploration of the implications of partial pressures and the conditions affecting the state of the substances. Some uncertainty remains regarding the treatment of water under different pressure conditions.

Contextual Notes

The discussion includes assumptions about the thermodynamic properties of the immiscible substance and the implications of partial pressures, which may not be fully resolved. The relationship between pressure, temperature, and phase states is central to the inquiry.

RoshDawg
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Hello, first post here.
Here is a hypothetical partial pressure of gas question

Imagine you have a two component system:
Component 1 is water
Component 2 is an imaginary substance that is immiscible with water, but has same boiling temp / pressure

You put the two components in a pressurized cylinder with equal molar volume distribution, and set the pressure to 1atm and 99°C (of course we know pure water will be liquid at this stage). Partial pressure law implies that water (or steam) will be exerting .5 atm, as would component 2 (.5 atm and 99°C will yield a vapor). Will there be liquid water or steam inside the cylinder?

Thanks for the help!
 
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RoshDawg said:
Hello, first post here.
Here is a hypothetical partial pressure of gas question

Imagine you have a two component system:
Component 1 is water
Component 2 is an imaginary substance that is immiscible with water, but has same boiling temp / pressure

You put the two components in a pressurized cylinder with equal molar volume distribution, and set the pressure to 1atm and 99°C (of course we know pure water will be liquid at this stage). Partial pressure law implies that water (or steam) will be exerting .5 atm, as would component 2 (.5 atm and 99°C will yield a vapor). Will there be liquid water or steam inside the cylinder?

Thanks for the help!
Suppose you had pure liquid water in a container (with no imaginary immiscible substance present), and you held the pressure at 0.5 atm (absolute) while raising the temperature to 99 C. What would the state of the contents of the container?

Chet
 
Chestermiller said:
Suppose you had pure liquid water in a container (with no imaginary immiscible substance present), and you held the pressure at 0.5 atm (absolute) while raising the temperature to 99 C. What would the state of the contents of the container?

Chet

You would be in a vapor phase
 
RoshDawg said:
You would be in a vapor phase
To be more precise, you would have superheated steam at 0.5 atm and 99 C. There would be no liquid water present. Now you do the same problem for the pure immiscible substance at 0.5 atm absolute and 99 C. What would be the state of the immiscible substance?
 
Chestermiller said:
To be more precise, you would have superheated steam at 0.5 atm and 99 C. There would be no liquid water present. Now you do the same problem for the pure immiscible substance at 0.5 atm absolute and 99 C. What would be the state of the immiscible substance?

Oh yes you are correct. Imagine the immiscible substance has the same thermodynamic properties. I am just wondering if water should be treated as if it is under 1atm conditions or .5atm due to partial pressure. Meaning if the water in the 1atm cylinder would have vaporized or remained as a liquid, when there is another substance in the cylinder taking up have the volume and exerting half the pressure.

Sorry if I am explaining the question poorly. I am vaporizing hydrocarbons and water and am wondering if I should take into account partial pressures or not.
 
RoshDawg said:
Oh yes you are correct. Imagine the immiscible substance has the same thermodynamic properties. I am just wondering if water should be treated as if it is under 1atm conditions or .5atm due to partial pressure. Meaning if the water in the 1atm cylinder would have vaporized or remained as a liquid, when there is another substance in the cylinder taking up have the volume and exerting half the pressure.

Sorry if I am explaining the question poorly. I am vaporizing hydrocarbons and water and am wondering if I should take into account partial pressures or not.
Yes. I understand what you are trying to figure out. I'm just trying to help you figure it out by leading you to the solution gradually. So, please answer my question in my previous post about the pure immiscible substance.

Chet
 
Chestermiller said:
Yes. I understand what you are trying to figure out. I'm just trying to help you figure it out by leading you to the solution gradually. So, please answer my question in my previous post about the pure immiscible substance.

Chet

The pure immiscible substance has the same thermodynamic properties as the water. So at .5atm and 99°C, it is a gas. At 1atm and 99°C, it is liquid.
 
RoshDawg said:
The pure immiscible substance has the same thermodynamic properties as the water. So at .5atm and 99°C, it is a gas. At 1atm and 99°C, it is liquid.
Excellent. Now you have a cylinder that has equal molar amounts of water and immiscible substance at 1 atm, such that the partial pressure of each is 0.5 atm. The temperature is 99C.

Assuming that they are both superheated vapors in the gas phase, what is the saturation temperature (dew point) for each of these substances corresponding to a saturation vapor pressure is 0.5 atm?

Chet
 
Chestermiller said:
Excellent. Now you have a cylinder that has equal molar amounts of water and immiscible substance at 1 atm, such that the partial pressure of each is 0.5 atm. The temperature is 99C.

Assuming that they are both superheated vapors in the gas phase, what is the saturation temperature (dew point) for each of these substances corresponding to a saturation vapor pressure is 0.5 atm?

Chet

The saturation temperature would be 82°C at .5atm for both substances
 
  • #10
RoshDawg said:
The saturation temperature would be 82°C at .5atm for both substances
So, if nothing would condense out, you have your answer to your original question.
 
  • #11
Okay, so just to recap, both fluids will be in gas phase since both should be in gas phase at .5 atm at 99C, even though the cylinder is set to 1atm, due to partial pressure of .5atm for each substance. Is this correct?
Thanks for your help in this.
 
  • #12
RoshDawg said:
Okay, so just to recap, both fluids will be in gas phase since both should be in gas phase at .5 atm at 99C, even though the cylinder is set to 1atm, due to partial pressure of .5atm for each substance. Is this correct?
Thanks for your help in this.

Yes. You pretty much doped this out for yourself.

Chet
 
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