Permutations & Combinations: Bankteller Problem

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SUMMARY

The discussion centers on solving the Bankteller Problem involving permutations and combinations. For Problem #1, the correct calculation for selecting 4 people, including 2 men and 2 women from a group of 6 males and 4 females, is determined using the formula (6 choose 2) * (4 choose 2), resulting in 90 possible combinations. Problem #2 addresses the probability of randomly selecting 2 men and 2 women from the same group, which requires further exploration of total combinations and favorable outcomes.

PREREQUISITES
  • Understanding of combinatorial mathematics, specifically permutations and combinations.
  • Familiarity with the binomial coefficient notation, such as "n choose k".
  • Basic probability concepts, including favorable outcomes and total outcomes.
  • Ability to perform calculations involving factorials.
NEXT STEPS
  • Research the concept of binomial coefficients and their applications in combinatorial problems.
  • Learn how to calculate probabilities in combinatorial contexts, focusing on favorable versus total outcomes.
  • Explore advanced topics in permutations and combinations, such as the Multinomial Theorem.
  • Practice solving similar problems involving combinations and permutations in real-world scenarios.
USEFUL FOR

Students studying combinatorial mathematics, educators teaching probability and statistics, and anyone looking to enhance their problem-solving skills in mathematical contexts.

rickdundee
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Homework Statement


There are 6 males and 4 females awaiting to see a teller at a bank.

Only 4 people can be served at one time.
1) How many ways can four of the people be picked and served one at a time, if they must include two(2) men and two(2) women?


2) If indeed the four people are picked randomly, what is the probability that the four will include two (2) men and two (2) women?
This is the question I am confused about.


The Attempt at a Solution


My solution for Problem#1: (6 choose 2) * (4 choose 2) = 90
 
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How many ways can you pick 4 people out of the 4 men and 6 women (with no restriction on how many men or women there are)?
 
That would be 10c4
 

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