Intro Statistics combination/probability problems.

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Homework Help Overview

The discussion revolves around combination and probability problems in introductory statistics. Participants are examining specific problems related to counting combinations of men and women, selecting numbers from a set, and calculating probabilities based on certain conditions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply combination and permutation concepts to solve the problems but expresses uncertainty about their counting methods and results. They question whether their reasoning aligns with the requirements of the problems.

Discussion Status

Some participants provide feedback on the original poster's calculations, particularly noting an error in the reasoning for one of the problems. There is an ongoing exploration of how to correctly approach the second problem regarding even numbers and their relation to being greater than 500.

Contextual Notes

Participants are working with incomplete problem statements and are relying on memory for the exact wording of the questions. This may affect their interpretations and approaches to the problems.

nontradstuden
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Hello. Am I counting right with these problems? I can't remember exactly how they were worded, but I remember what they were asking...

1) Given 20 men and 20 women, how many groups of 12 can you make with 6 men and 6 women.

I said 20.Combination.6 * 20.Combination.6.

2) given S= {1, 2, 4, 5, 7}, you will choose 3 randomly from the set. What's the probability of getting an even number greater than 500?

I said 12 / 5.Permutation.3.

How I got 12:

1. 3 ways of having 5 first, 2 last.
2. 3 ways of having 5 first, 4 last.
3. 3 ways of having 7 first, 2 last.
4. 3 ways of having 7 first, 4 last.

Added it up to get 12. I then divided it by a permutation because order is important?...


3) What is the probability that two randomly chosen people were both not born in June?

I said P(First not born in June ^ Second not born in June)= (11/12) * (11/12)



Is my counting right? Thanks for your help.
 
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nontradstuden said:
Hello. Am I counting right with these problems? I can't remember exactly how they were worded, but I remember what they were asking...

1) Given 20 men and 20 women, how many groups of 12 can you make with 6 men and 6 women.

I said 20.Combination.6 * 20.Combination.6.

2) given S= {1, 2, 4, 5, 7}, you will choose 3 randomly from the set. What's the probability of getting an even number greater than 500?

I said 12 / 5.Permutation.3.

How I got 12:

1. 3 ways of having 5 first, 2 last.
2. 3 ways of having 5 first, 4 last.
3. 3 ways of having 7 first, 2 last.
4. 3 ways of having 7 first, 4 last.

Added it up to get 12. I then divided it by a permutation because order is important?...


3) What is the probability that two randomly chosen people were both not born in June?

I said P(First not born in June ^ Second not born in June)= (11/12) * (11/12)



Is my counting right? Thanks for your help.

You counting for (2) is incorrect. If you first pick 5, then picking any two other numbers gives you a result > 500. If you first pick 7, then picking any two other numbers gives you a result > 500. If you pick anything other than 5 or 7 first you will not get a result > 500.

RGV
 
@Ray Vickson,

Thanks for your help.

For number 2, they have to be even and >500, how do I go about solving that part?
 
nontradstuden said:
@Ray Vickson,

Thanks for your help.

For number 2, they have to be even and >500, how do I go about solving that part?

Surely you know what an even number looks like!

RGV
 

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