How Do Ferrite Beads Suppress High Frequency Signals?

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Ferrite beads suppress high-frequency signals by acting as inductive and lossy impedance to the magnetic fields generated by AC RF currents in conductors. They are not part of the electrical circuit but function as a one-turn ferrite core inductor when placed over cables. The ferrite materials used are specifically lossy at RF frequencies, allowing them to maintain a consistent impedance that flattens out at a loss value instead of resonating. This characteristic is particularly effective in the medium frequency RF range, typically between 100MHz and 300MHz, where electromagnetic interference (EMI) is prevalent. Ferrite beads are commonly found on USB and other cables to mitigate high-frequency noise.
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I think we have all seen them on usb cables or some other cable. I know they act as a resistor for high frequency signals. How can they attenuate the HF signals when they are not electrically in the circuit (like a RC filter).
 
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They are acting as a 1-turn ferrite core inductor when they are just put over a cable like that. The AC RF current in the conductor generates a magnetic field that circulates around the conductor, and the ferrite ring acts as an inductive and lossy impedance to that field.

The ferrite materials that are used for RF EMI supression beads, baluns and chokes are lossy at RF frequencies. So instead of the impedance versus frequency characteristic climbing inductively up to the LC resonant frequency (with the parasitic capacitance) and then coming back down capacitively, the impedance characteristic climbs inductively, and then flattens out at the loss value (measured in Ohms), where it stays through much of the medium frequency RF range, where EMI is typically a problem (say, 100MHz-300MHz).

Lots more info here: http://fair-rite.com/
 
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