Thermal Expansion of Gas in a Tank

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SUMMARY

The discussion focuses on calculating the thermal expansion of gasoline in an underground tank when the temperature changes from 54°F to 82°F. The linear coefficient of expansion for gasoline is given as 9.6e-4, which is used to derive the volume expansion formula. The correct calculation shows that the volume expansion results in an increase of 88.7 gallons, leading to a total of 1188.7 gallons that can be poured into the tank. The participants clarify the relationship between linear and volume coefficients of expansion, confirming that the linear coefficient already accounts for the necessary multiplication factor.

PREREQUISITES
  • Understanding of thermal expansion concepts
  • Familiarity with the linear and volume coefficients of expansion
  • Basic algebra for manipulating equations
  • Knowledge of temperature conversion and measurement
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  • Study the derivation of the volume expansion formula, ΔV = β V₀ ΔT
  • Research the thermal expansion coefficients for various liquids
  • Explore practical applications of thermal expansion in engineering
  • Learn about temperature effects on fuel storage and transportation
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Students in physics or engineering courses, professionals in the fuel industry, and anyone interested in the principles of thermal expansion and its practical implications.

slong89
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Homework Statement



An underground gasoline tank at 54°F can hold 1100 gallons of gasoline. If the driver of a tanker truck fills the underground tank on a day when the temperature is 82°F, how many gallons, according to his measure on the truck, can he pour in? Assume that the temperature of the gasoline cools to 54°F on entering the tank.

Homework Equations



(delta)Length = 3(alpha) * Volume(initial) * (delta)Temp
i found the value alpha for gasoline to be 9.6e-4

The Attempt at a Solution



3(9.6e-4)(28)(1100)=delta(L)=88.7
thus the amount he could pour in is 1188.7
for some reason this isn't the answer though... I'm not really sure what I'm doing wrong
 
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The equation for volume expansion will look like this:
\Delta V = \beta V_0 \Delta T

where \beta is the volume coefficient of expansion, which would be about 3 times the linear coefficient. Are you sure you found the linear coefficient of expansion for gasoline?
 
You're right.. thank you so much. The 9.6e-4 already accounted for the times 3, and thus was the volume coefficient of expansion. I guess you couldn't really make one for gasoline anyway. Thanks again.
 

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