Gravitation and Circular Orbits

In summary, the energy needed to launch a satellite of mass m into circular orbit at altitude h is equal to (\frac {GMm}{R})(\frac{R+2h}{2(R+h)}), where R is the radius of the Earth and M is the mass of the Earth. This can be derived by expanding the equation and equating it to the work done in launching the satellite. The energy is equal to the sum of potential and kinetic energy in orbit minus the potential energy on the surface of the Earth.
  • #1
kevi555
17
0
Just a question about gravitation equations:

Neglecting Earth's rotation, show that the energy needed to launch a satellite of mass m into circular orbit at altitude h is equal to:

[tex](\frac {GMm}{R})(\frac{R+2h}{2(R+h)})[/tex]

Where R = the radius of the Earth and M = the mass of the Earth.

I've tried subbing in r=h+R and it hasn't given me much help.

Any help would be truly appreciated! Thanks all.
 
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  • #2
Try expanding the equation and see what you get. (HINT: think [tex]W=-\Delta U_g[/tex])
 
  • #3
"W" as in work? or what variable?
 
  • #4
kevi555 said:
"W" as in work? or what variable?

Work.
 
  • #5
kevi555 said:
Just a question about gravitation equations:

Neglecting Earth's rotation, show that the energy needed to launch a satellite of mass m into circular orbit at altitude h is equal to:

[tex](\frac {GMm}{R})(\frac{R+2h}{2(R+h)})[/tex]

Where R = the radius of the Earth and M = the mass of the Earth.

I've tried subbing in r=h+R and it hasn't given me much help.

Any help would be truly appreciated! Thanks all.

What is the force that makes a body go round in a circle? What is supplying that force here? You have to equate the two.
 
  • #6
Some addition which I didn't bother to mention:

Energy reqd = (PE + KE) in orbit - PE on surface of earth. You have to use the previous concept anyway.
 

Related to Gravitation and Circular Orbits

1. What is gravitation?

Gravitation is a fundamental force of nature that causes objects with mass to be attracted to each other. It is responsible for the motion of celestial bodies such as planets, stars, and galaxies.

2. How does gravity affect circular orbits?

Gravity is the force that keeps objects in circular orbits. It acts as a centripetal force, pulling an object towards the center of the orbit and preventing it from flying off into space. The strength of the gravitational force depends on the mass of the objects and the distance between them.

3. Why do planets orbit the sun in an elliptical shape?

According to Kepler's laws of planetary motion, planets orbit the sun in elliptical shapes due to the varying strength of the gravitational force as they move closer or farther away from the sun. The sun is located at one of the foci of the ellipse.

4. Can circular orbits exist without gravity?

No, circular orbits cannot exist without gravity. The centripetal force required to maintain the circular motion is provided by the gravitational force between the objects in orbit. Without gravity, the objects would move in a straight line instead of a circular path.

5. How does the mass of an object affect its orbit?

The mass of an object affects its orbit by determining the strength of the gravitational force between it and the other objects in the system. The greater the mass, the stronger the force, and the tighter the orbit. This is why smaller objects, such as satellites, have faster orbits around larger objects, such as planets.

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