How Does Temperature Affect Radioactive Decay Rates?

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Discussion Overview

The discussion centers on the relationship between temperature and radioactive decay rates, exploring whether heating a radioactive substance affects its decay rate. Participants examine theoretical implications, mathematical formulations, and the conditions under which temperature might influence radioactivity.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • Some participants propose that heating a radioactive substance reduces its radioactivity due to relativistic thermal motion of the atoms.
  • Others argue that significant thermal energy would need to be achieved for relativistic effects to be relevant, suggesting temperatures in the billions of degrees are necessary.
  • A mathematical expression for the decay rate as a function of temperature is presented, indicating that the effect of temperature on decay rates is minimal.
  • One participant questions the relationship between radiation as a nuclear property and temperature as an atomic property, suggesting that the two may not be directly linked.
  • There is a reiteration of the mathematical formulation for the decay rate, with a request for verification of its correctness.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the impact of temperature on radioactive decay rates, with multiple competing views and uncertainties remaining regarding the significance of thermal effects.

Contextual Notes

Participants note that the thermal energies of atoms at typical temperatures are much lower than the rest mass energy of nucleons, which raises questions about the practical relevance of temperature effects on decay rates.

Who May Find This Useful

This discussion may be of interest to those studying nuclear physics, thermodynamics, or the interplay between temperature and atomic behavior in radioactive materials.

DiamondGeezer
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I know that if a radioactive substance is heated, then the radioactivity is reduced because of the relativistic thermal motion of the atoms.

Is there a formula linking radioactive decay, temperature and perhaps, heat capacity?
 
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DiamondGeezer said:
I know that if a radioactive substance is heated, then the radioactivity is reduced because of the relativistic thermal motion of the atoms.

The problem is that in order for this to be significant, the thermal energy of the particles needs to be of the order of their rest masses. Now, the rest mass of a single proton or neutron (expressed in energy units) is of the order of 1 GeV. At a temperature of 11 000 K, the average thermal energy of a particle is about 1 eV (that's given by the ratio of the Boltzmann constant and the elementary charge). So in order for hydrogen atoms to have thermal energies which make them move relativistically in a significant way, we'd have to heat them to about 11 000 billion degrees. In order to do so for a radioactive nucleus with about 100 protons and neutrons, that's 100 times more even.

But by that time, they are undergoing already a lot of nuclear interactions!
 
To the first order of magnitude you're looking at something like this

\lambda' = \lambda / (3/2 kT/mc^2 + 1)

where \lambda is the rate of decay, k is Boltzmann constant, T is temperature, and m is mass of the atom.

The effect is there but it's tiny. You'd have to heat the substance to billions of degrees to get anything remotely measurable.
 
DiamondGeezer said:
I know that if a radioactive substance is heated, then the radioactivity is reduced because of the relativistic thermal motion of the atoms.

Is there a formula linking radioactive decay, temperature and perhaps, heat capacity?
Relativistic thermal motion would imply an extraordinarily high temperature - some thing beyond normal experience in the terrestrial environment.

Radiation is a nuclear property as opposed to temperature and heat capacity (or specific heat) which are atomic or interatomic properties.
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/temper.html
A convenient operational definition of temperature is that it is a measure of the average translational kinetic energy associated with the disordered microscopic motion of atoms and molecules.

Thermal energies of atoms are on the order of 0.02 eV at about room temperature.
 
hamster143 said:
To the first order of magnitude you're looking at something like this

\lambda' = \lambda / (3/2 kT/mc^2 + 1)

where \lambda is the rate of decay, k is Boltzmann constant, T is temperature, and m is mass of the atom.

The effect is there but it's tiny. You'd have to heat the substance to billions of degrees to get anything remotely measurable.

Let's see that first approximation again:

\lambda' = \frac{\lambda}{ \frac{\frac{3}{2}kT}{mc^2} +1}

Is that correct?
 

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