E field profile in a capacitor with two different dielectric material

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SUMMARY

The discussion centers on the behavior of electric fields in a capacitor containing two different dielectric materials. When a fixed voltage is applied, the electric field (E-field) is not constant across the two layers due to their differing dielectric constants. The material with the higher dielectric constant stores more energy and experiences a smaller voltage drop, confirming that the voltage drop is inversely related to the dielectric constant. This conclusion is illustrated by comparing two capacitors in series, each with different dielectric materials.

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  • Understanding of capacitor fundamentals
  • Knowledge of dielectric materials and their properties
  • Familiarity with electric field concepts
  • Basic principles of energy storage in capacitors
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Electrical engineers, physics students, and anyone involved in capacitor design and analysis will benefit from this discussion.

enroger0
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Hi everyone, this is not a homework, I'm actually dealing with the case in real life here. If this turns out to be standard textbook stuff then I'm sorry as I haven't studied this before.

Suppose a plate capacitor has two different dielectric material layer sandwiched in it. Then a fixed voltage is applied on it.

The simplest consideration would be that E field is constant everywhere despite the different dielectric constant of the two layers, this was my first thought. But it didn't feel right as I consider the energy, since system tends to minimize energy against fixed boundary condition.

So with the same E-field strength, the material will store more energy with a higher dielectric constant. Minimizing the energy will yield that the higher dielectric constant material will have a smaller voltage drop across it, is this result right?
 
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The easiest way to think about this is to imagine two real capacitors with same plate areas, connected in series, one with the one dielectric and its thickness, and the second dielectric and its thickness. Now apply voltage to the two caps in series, and calculate the voltage across each cap.
 
Ha! Dumb me... Then it is true that voltage drop faster in smaller dielectric material. Thanks
 

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