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urduworld
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please help me to findout this problem
i am putting this question second time bcoz i was unable to findout its category i am new here
answer should be 2(pi)a
urduworld said:we will find value of y from eq 1 + y^2 = a^2 - x^2
i will put it (dy/dx)^2
urduworld said:1. i have try my best and i and reach at a point and unable to solve it complete please help me to find the parameter of the circle
.2 also what limit i should apply ( i am thinking to apply 2(pi)a/4) am i right
Mark44 said:You posted the same problem in another thread: https://www.physicsforums.com/showthread.php?t=354071.
You shouldn't start a new thread for the same problem.
Also, the distance around a circle is its circumference, or perimeter. Parameter means something different.
urduworld said:yes i have posted this second time because that time i can't got answer :(
No, not an ordinary substitution - a trig substitution. Do you know how to do one of these substitutions?urduworld said:ohh i really got point i have got that i have have to substitute a^2 - x^2 with (u or any alphabet) and then i have to apply limit am i right Thanks tiny :)
urduworld said:ohh i really got point i have got that i have have to substitute a^2 - x^2 with (u or any alphabet) and then i have to apply limit am i right Thanks tiny :)
urduworld said:then what i have to do i can't understand trig substitution :(
The formula for finding the circumference of a circle using integration is C = 2π∫r dr, where r is the radius of the circle.
Integration helps in finding the parameters of a circle by allowing us to calculate the area and circumference of the circle using the definite integral of the circle's equation.
To find the parameters of a circle using integration, first we need to express the equation of the circle in terms of x or y. Then, we use the definite integral to calculate the area or circumference of the circle by integrating the equation from the limits of the circle's radius.
Yes, the limitations to using integration to find the parameters of a circle include the complexity of the circle's equation and the need for advanced calculus knowledge to perform the integration.
Yes, integration can also be used to find other parameters of a circle such as the arc length, sector area, and volume of a sphere.