What Are the Final Velocities After a Two-Dimensional Collision?

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In a two-dimensional collision problem, two objects, each with a mass of 6 kg, are analyzed before and after the collision. The first object moves at 3 m/s before the collision and deflects at a 40-degree angle to the left after the collision, while the second object, initially at rest, moves to the right of the first object's original path. The conservation of momentum equations for both x and y directions are applied to find the final velocities of each object. Since the masses are equal, they can be simplified out of the equations. The discussion emphasizes the importance of correctly applying the equations with the given angles to solve for the final velocities.
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problem:
before - 1st object: m=6kg, v=3m/s
2nd object: m=6kg, v=0m/s
after - 1st object move off in a direction 40 degree to the left of its original path
2nd move to the right of the first's original path
find the speech of each object after the collision
equations:
x-direction: m1v1ix + m2v2ix = m1v1fx + m2v2fx
y-direction: m1v1iy + m2v2iy = m1v1fy + m2v2fy
 
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Welcome to PF!

Hi hdo! Welcome to PF!: :smile:

(try using the X2 tag just above the Reply box :wink:)
hdo said:
… 2nd move to the right of the first's original path

Do you mean at 90º?

ok, those are the correct equations … now put the numbers in …

what do you get? :smile:​

(btw, all the masses are the same, 6 kg, so you can leave them all out! :wink:)
 

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