Radius of curvature of a bimetallic strip

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Homework Help Overview

The discussion revolves around calculating the radius of curvature of a bimetallic strip subjected to different temperatures for each metal. The original poster describes a scenario where one metal is at 180°C and the other at 160°C, seeking assistance from those knowledgeable in solid mechanics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between temperature differences and the resulting curvature, with references to coefficients of thermal expansion. There is also a mention of a distinction between bimetallic and bimaterial strips, raising questions about the applicability of the same principles.

Discussion Status

Some participants have offered guidance on using coefficients of expansion to approach the problem, while others are exploring different material configurations. The conversation reflects a mix of interpretations and attempts to clarify the problem setup without reaching a consensus.

Contextual Notes

There are indications of varying material types and temperatures, which may affect the assumptions made in the calculations. The original poster and another participant note differences in material composition, which could influence the approach to finding the radius of curvature.

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Homework Statement



I need to calculate the radius of curvature of a bimetallic strip when the two strips are subjected to different temperatures. in the problem, the two metals themselves are in different temperatures. One at 180°C, other at 160°C. Anyone with good solid mechanics knowledge will do. Any suggestion will be highly appreciated.



Homework Equations



Define L = strip length, dL = L1-L2 at that temp. difference, and T = thickness of one metal layer. When bent to the required radius r, the inner-outer layer arc length difference due to a radius difference of T equals dL.

Thus theta*((r+T/2)-(r-T/2)) = dL, where theta = L/r.
Then LT/r = dL ==> r = LT/dL.

The Attempt at a Solution



Need help here
 
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welcome to pf!

hi drakierd! welcome to pf! :wink:
drakierd said:
r = LT/dL.

that's it! :smile:

you know T, and you can find dL/L from the given coefficients of expansion of the two metals (i assume they are given?) :wink:
 
Hi,

In my case, it is not a Bimetal strip, it is a bimaterial strip. And one material is glass and the other one is few microns Iron deposited on it. And finally the glass is 160C and the metal is 180C. And the question is that I need to know the radius of curvature of this thing. Any suggestions for that?
 
welcome to pf!

hi shouhardo! welcome to pf! :smile:

can't you use coefficients of expansion in exactly the same way?
 
yeah I can. You are right, that's how I have to do it.
 

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