Angular acceleration and linear acceleration

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Angular acceleration is related to linear acceleration through the equation α = a/r, where α is angular acceleration, a is linear acceleration, and r is the radius. The direction of angular acceleration points towards the axis of rotation, while linear acceleration has both radial and tangential components. The tangential component arises from the angular acceleration, indicating that as a rotating object accelerates, points on the object experience both types of acceleration. The relationship between angular velocity and linear velocity is expressed as ω = v/r, and the time derivatives of these equations help establish the connection between the two forms of acceleration. Understanding these relationships is crucial for analyzing the motion of rotating bodies in physics.
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For a disk in the x-y plane that is rotating about the z-axis which travels through its center of mass, how does the angular acceleration relate to the linear acceleration of a particle on the body? Is the direction and the magnitude both affected? How do we calculate these in vector form? I would greatly appreciate it if someone would enlighten me about this.
 
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The angular velocity is related to the linear velocity by:
\omega = \dot \theta = \frac{v}{r}

Taking the time derivative of both sides and using that r is independent of time:

\alpha = \ddot \theta = \frac{a}{r}

The direction is always pointing towards the axis of rotation.
 
Thanks for replying, but would there be a tangential component? And if alpha=a/r, how is it that the linear acceleration is maintained constant?
 
For a rotating object undergoing an angular acceleration, a point on that object will have both a radial and tangential component of linear acceleration:
a_r = \omega^2 r
a_t = \alpha r
 
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