SU(N) symmetry in harmonic oscillator

tom.stoer
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Starting with the D-dim. harmonic oscillator and generators of SU(D)

T^a;\quad [T^a,T^b] = if^{abc}T^c

one can construct conserved charges

Q^a = a^\dagger_i\,(T^a)_{ik}\,a_k;\quad [Q^a,Q^b] = if^{abc}Q^c

satisfying the same algebra and commuting with the Hamiltonian

H = a^\dagger_i\,1_{ik}\,a_k + \frac{N}{2} = \sum_{i=1}^D a^\dagger_i a_i + \frac{N}{2};\qquad [H,Q^a] = 0

where I introcuced a new generator for U(1).

That means that the states

|n_1, n_2, \ldots n_N\rangle;\quad \sum_{i=1}^D n_i = N

are related to integer- or vector-representations of SU(D).

The degeneracy for fixed N is calculated as

\text{dim}\,N_D = \left(\array{N+D-1 \\ N}\right)

Questions:
- how are SU(D) vector representations labelled (compared to |lm> for SU(2))
- what are their dimensions (compared to 2l+1 for l-rep. in SU(2))
- and how do the dimensions sum up to dim ND

Thanks
 
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Checking this explicitly for the simplest cases SU(2) and SU(3) it becomes strange already:


SU(2)

N=0: |00> is the trivial 1-rep. of SU(2)

N=1: |10>, |01> is the 2-rep. of SU(2); but this is a spinor rep. with l = 1/2 and 2l+1 = 2

N=2: |20>, |11>, |02> is the 3-rep. of SU(2)


SU(3)

N=0: |000> is the trivial 1-rep. of SU(3)

N=1: |100>, |010>, |001> is a 3-rep. of SU(3); again this is not a vector rep.; and I know there are two 3-reps, 3 and 3*

N=2: |200>, ... |110>, ... is a 6-dim. rep. of SU(3) which seems to be a sum of the two 3-reps 6 = 3 + 3*, correct?

N=3: here I find dim 33 = 10; now this can either be the 10-dim. irreducible rep., or just 1+3+6


So my first conclusion from SU(2) is that I have to include half-integer reps as well; this is strange, but OK. But for SU(3) it's unclear how to arrange rep's and how to count them.
 
Tom, the general theory of unitary representations of SU(n) is developed in Chapter 13 of Wu Ki Tung's Group Theory book and is derivable from the general theory of representations of GL(n) as it's done in the book.

For the 3-dim isotropic oscillator a thorough investigation from a group theoretical perspective is made by Wybourne in his book in Chapter 20.
 
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This is equivalent to the problem of populating N cells with bosons. The states are labeled by the occupation numbers n1, n2,... nN where n = ∑ ni. The representation of SU(N) is the symmetric part of the n-fold tensor product (N ⊗ N ⊗ ... ⊗ N)sym, a reducible representation.
 
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