Solving Equations of Motion: When Will 100g Mass Overtake 1.5kg Shot Put?

Click For Summary
SUMMARY

The discussion focuses on solving the equations of motion to determine when a 100g mass will overtake a 1.5kg shot put dropped from a height of 60m. The two methods presented include using the standard equations of motion for both objects and simplifying the problem to a relative velocity scenario, neglecting air friction. The equations derived are S(1) = 70 - 10t - 0.5gt² for the shot put and S(2) = 60 - 0.5gt² for the 100g mass. The key takeaway is that both objects experience the same gravitational acceleration, allowing for a straightforward comparison of their positions over time.

PREREQUISITES
  • Understanding of basic physics concepts, specifically equations of motion.
  • Familiarity with gravitational acceleration (g = 9.81 m/s²).
  • Knowledge of relative velocity principles.
  • Ability to solve quadratic equations.
NEXT STEPS
  • Study the derivation and application of the equations of motion in physics.
  • Learn about gravitational acceleration and its effects on falling objects.
  • Explore relative velocity problems in physics for a deeper understanding.
  • Practice solving quadratic equations to enhance problem-solving skills.
USEFUL FOR

Physics students, educators, and anyone interested in understanding motion dynamics and solving related problems in classical mechanics.

][nstigator
Messages
24
Reaction score
0
Two physics students conduct the following experiment from a very high bridge. Thao drops a 1.5kg shot put from a vertical height of 60m while at exactly the same time Benjamin throws a 100g mass with an initial downwards velocity of 10 m/s from a point 10m above Thao.

At what time will the 100g mass overtake the shot-put?
 
Physics news on Phys.org
There are two ways to set up this problem:

1. Use the usual equations of motion for body 1 (the heavier mass) and 2 (the lighter mass).

S(1) = 70 -10t - 0.5gt^2
S(2) = 60 - 0.5gt^2

Then solve for the time when their positions are the same.

2. Since the acceleration of both objects are the same under gravity, you may notice that this can be reduced to a simple relative velocity problem.
 
And one more thing,though you're give the masses,you may very well neglect air friction.The fact that they give you the masses was just for identification.

Daniel.
 

Similar threads

Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 15 ·
Replies
15
Views
27K