Solving 2nd Order Linear DE with Constant Coefficients

  • Thread starter Thread starter Apteronotus
  • Start date Start date
  • Tags Tags
    2nd order Linear
Apteronotus
Messages
201
Reaction score
0
Hi,

When solving a 2nd order Linear DE with constant coefficients (ay''+by'+cy=0) we are told to look for solutions of the form y=e^{rt} and then the solution (if we have 2 distinct roots of the characteristic) is given by
y(t)=c_1 e^{r_1 t}+c_2 e^{r_2 t}

This is clearly a solution, but how do we know there are no other solutions?
That is, how do we know this is the general solution?
 
Physics news on Phys.org
Hi Apteronotus! :smile:
Apteronotus said:
… how do we know there are no other solutions?

It's easy to prove for the first-order case …

if y' - ry = 0, put y = zert, then (z' + rz)ert = rzert

so ert = 0 (which is impossible),

or z' + rz = rz, ie z' = 0, ie z is constant :wink:

and now try (y' - ry)(y' - sy) = 0, using the same trick twice :smile:
 
There is the following linear Volterra equation of the second kind $$ y(x)+\int_{0}^{x} K(x-s) y(s)\,{\rm d}s = 1 $$ with kernel $$ K(x-s) = 1 - 4 \sum_{n=1}^{\infty} \dfrac{1}{\lambda_n^2} e^{-\beta \lambda_n^2 (x-s)} $$ where $y(0)=1$, $\beta>0$ and $\lambda_n$ is the $n$-th positive root of the equation $J_0(x)=0$ (here $n$ is a natural number that numbers these positive roots in the order of increasing their values), $J_0(x)$ is the Bessel function of the first kind of zero order. I...
Are there any good visualization tutorials, written or video, that show graphically how separation of variables works? I particularly have the time-independent Schrodinger Equation in mind. There are hundreds of demonstrations out there which essentially distill to copies of one another. However I am trying to visualize in my mind how this process looks graphically - for example plotting t on one axis and x on the other for f(x,t). I have seen other good visual representations of...
Back
Top