How do I find deflection in this beam?

  • Thread starter Thread starter raymanmusic
  • Start date Start date
  • Tags Tags
    Beam Deflection
Click For Summary

Discussion Overview

The discussion revolves around calculating the deflection at point C of a beam with specified boundary conditions and material properties. Participants explore various methods and equations related to beam deflection, including the unit load method and specific formulas for different loading conditions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested
  • Homework-related

Main Points Raised

  • One participant asks how to find the deflection at point C, providing details about the beam's supports and material properties.
  • Another participant emphasizes the need for specific parameters such as the modulus of elasticity (E), moment of inertia (I), and lengths of segments (LAB and LBC) to solve the problem.
  • A participant mentions using the unit load method and provides specific values for I, E, and distances between points A and B, and B and C.
  • One participant reports obtaining a different deflection answer using a different method, indicating a potential disagreement on the results.
  • Another participant claims to have verified their answer using two different methods, expressing high confidence in their result.
  • There is a discussion about the placement of unit loads and the treatment of triangular loads in calculations, with participants clarifying their approaches to finding deflection.
  • A participant shares a formula for calculating deflection, followed by specific values and calculations leading to a result of -72.
  • Another participant confirms the correctness of a previously calculated deflection value, providing a more precise rounded answer.

Areas of Agreement / Disagreement

Participants express differing results for the deflection at point C, indicating that multiple competing views remain. While some participants agree on the correctness of certain calculations, others challenge or refine earlier claims without reaching a consensus.

Contextual Notes

Some participants mention specific assumptions and simplifications in their calculations, such as treating EI as a constant or ignoring certain loads, which may affect the results. The discussion includes various mathematical steps that remain unresolved.

raymanmusic
Messages
30
Reaction score
1
How do I find deflection (displacement) in point C at the end of the beam? Answer is to be given in mm. There is a roller connection (only Fy) in B and an external pin in A (Fy and Fx). The module of elasticity and area moment of inertia is given.

2vwzre8.jpg


Relevant equations:
1. http://en.wikipedia.org/wiki/Deflection_(engineering)
2. http://www.advancepipeliner.com/Resources/Others/Beams/Beam_Deflection_Formulae.pdf


Here is a solution to a similar problem: https://dl.dropboxusercontent.com/u/11241083/beer_mecanica_4e_solucionario_c09_a.pdf
 
Last edited by a moderator:
  • Like
Likes   Reactions: 1 person
Physics news on Phys.org
First, you are going to need to know E, I, and LAB and LBC.
 
I tried solving this using the unit load method.
I = 57.9 * 10^6 (mm^4)
E = 2.1 * 10^5 (N/mm^2)
AB distance = 3 meters
BC distance = 2 meters

https://dl.dropboxusercontent.com/u/11241083/Solution_Beam_Problem.pdf
 
Last edited by a moderator:
raymanmusic: I currently got an answer different from your post 3 answer for deflection of point C, using a different method.
 
Last edited by a moderator:
raymanmusic said:
How do I find deflection (displacement) in point C at the end of the beam? Answer is to be given in mm. There is a roller connection (only Fy) in B and an external pin in A (Fy and Fx). The module of elasticity and area moment of inertia is given.

2vwzre8.jpg


Relevant equations:
1. http://en.wikipedia.org/wiki/Deflection_(engineering)
2. http://www.advancepipeliner.com/Resources/Others/Beams/Beam_Deflection_Formulae.pdf


Here is a solution to a similar problem: https://dl.dropboxusercontent.com/u/11241083/beer_mecanica_4e_solucionario_c09_a.pdf
You failed to use the template which was provided. Do not do this again, we have rules for a reason and they must be followed.

Answers discussed in OP's first thread.

https://www.physicsforums.com/showthread.php?t=711176
 

Attachments

  • homework1.jpg
    homework1.jpg
    8.3 KB · Views: 539
Last edited by a moderator:
raymanmusic: I now also used a second method, and I got exactly the same answer I got using a completely different method in post 4. Therefore, I am about 99 % certain I have the correct answer.

You did excellent work in post 3, but it appears you made one main mistake, as follows. Delete your unit load at x2 = 666,67 mm, and then try your solution again. You do not want to find deflection at x2 = 666,67 mm, and you therefore should not place a unit load at x2 = 666,67 mm. Try again.

By the way, always maintain four significant digits throughout all your intermediate calculations, then round only the final answer to three significant digits. E.g., -7,556 kN, not -7,56 kN.
 
Thanks for helping me out nvn. Do I place the unit load where I want to find deflection? What about the triangle load? Should I ignore it when I calculate mx2? What did you get as your final answer in mm?
 
raymanmusic: Yes, place the unit load where you want to find deflection. Yes, ignore the triangular load when you compute mx1 and mx2. I will let you know if you obtain the correct final answer, if this is not a test question.
 
Last edited:
I got approximately 5.922 mm as my final answer. Is this close to the correct answer?
 
  • #10
Excellent work, raymanmusic. Your answer is correct (5.921 54, which rounds to 5.92 mm).

By the way, N/mm^2 is called MPa. If a derived unit has a standardized special name, then only the standardized[/color] special name should be used. E.g., 210 000 MPa, not 210 000 N/mm^2.
 
Last edited:
  • Like
Likes   Reactions: 1 person
  • #11
Thanks for the help nvn. I'll ask you if I have more problems I'm stuck with.
 
  • #12
deflection101 came with a formula for this case,Where is it?
 
  • #13
Yc=[wb^3(5L-2b)+30PLb^2] / 90
 
  • #14
given: w=10kn/m
p=8kn/m
a= 3
b=2
EI=1 (to simplify)

Ans.:yc= - 72 (-160/3 - 56/3)
 
Last edited:
  • #15
it doesn't get any better than this! yc= - 72
 
  • #16
EIy(x)=wx/360b(3x^4-15bx^3+30b^2X^2-30b^3X-20ab^3)+Px/6(x^2-3bx-2ab)
EIy(2)=-72
y=- 72/EI EI=read above
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
3
Views
4K