Constrained motion Definition and 23 Threads

Consider the following setup where the bead can glide along the rod without friction, and the rod rotates with a constant angular velocity ##\omega##, and we want to find the constraint force using Lagrange multipliers. I chose the generalized coordinates ##q=\{r,\varphi\}## and the...

I've got a couple of questions concerning holonomic constraint equations: 1- Suppose I've got k holonomic constraint equations for n particles, how can I be sure those are all the ones there are and I didn't miss any? I mean, in a given situation, I can be pretty sure that I've got all, but is...

Someone pls solve this. I've done it but I'm not sure if it's correct. Thanks!

I tried 1. using the Lagrangian method: From ##y=-kx^2## I got ##\dot y = -2kx \dot x## and ##\ddot y = -2k \dot x^2 - 2 kx \dot x##. (Can I use ##\dot y = g## here due to gravity?) This gives for kinetic energy: $$T = \frac{1}{2} mv^2 = \frac{1}{2} m (\dot x^2 + \dot y^2) = \frac{1}{2} m (\dot...

How do you set the direction for this problem? Do you look at the motion of the block? If you set right positive, does that automatically makes upward motion positive? I set right as positive and up as positive for this problem. However, my answer was wrong. Textbook solution set right as...

I tried getting the velocity of a which by using constraint came out to be 3 and by using the eqn for vcom i got the ans as 3.5 i just want to confirm is this the correct answer

Homework Statement Under the action of force P the constant acceleration of B is 6 m/s^2 up the incline as in figure. For the instant when B's velocity is 3 m/s up incline, what is the velocity of point C? How do I solve this using constraints? [/B] Homework Equations For a pulley system ΣT.v...

Homework Statement Homework Equations ## v = r \omega## The Attempt at a Solution Velocity of point B= ##v_B = 4 \times \omega = 4 ## m/s Since the separation between B and C is constrained to be a constant, Velocity of B along rod = Velocity of C along the rod ## \Rightarrow v_B \cos \theta...

Hi everyone! Really struggling with this question here, was hoping someone could point me in the right direction? https://puu.sh/xVitw/4c0b89c576.png 1. Homework Statement Set origin to bottom right. OA is y (Which using cos(60)*R you can determine to be 0.5R). OB is x (which you can...

Homework Statement Determine the speed with which block B rises in figures if the end of cord at A is pulled down with a speed of 2ms^-1 Homework Equations Given Velocity downwards at A=2m/s The Attempt at a Solution Really stuck... Couldn't even start the question solving...I know all...

I have been having some problem resolving the velocity component along the rope. My question will be clear if you read an illustration that I encountered which is very helpful in showing my doubt very clearly. In the Fig. given below the block ##'A'## and ##'B'## are connected with an...

Homework Statement In the figure shown, friction force between the bead and the light string is ##\dfrac{mg}{4}##. Find the time in which the bead looses contact with the string after the system is released from rest. Homework Equations Weight of the bead ##(m_1)=mg## Friction acting on the...

Homework Statement Three identical charged balls of mass m and charge q bound in a triangle thread length l. One of the strands break. Calculate the acceleration of the middle ball at the initial moment. 2. Relevant equation a. Newton's laws ##m\vec a_1 = \vec F_{12} +\vec F_{13} + \vec...

Homework Statement In this, if I want the acceleration constraint between M and 2M, I write $$AM+2AB$$=LENGTH OF STRING, which on differentiating twice gives $$a_{m}=2a_{2m}$$(which turns out to be correct). However, if we look closely, the, lower end of string is FIXED to the pulley A, and...

Homework Statement A pulley fixed on a wall of height h connects a toy boat with a man on the wall. The string is pulled by the man at a constant speed u m/s. Find the velocity of boat when the string makes an angle $$\theta$$ with the water. Homework Equations The question will be more...

[Mentors note: Thread moved from the Classical Physics forum after it had been replied to, hence the lack of a homework template] Hey I have been trying to solve this problem for the last few days with no luck. Question: a car starts from rest at the origin and travels along the path given by...

Hello fellow PF members I was wondering how one would go about finding the lagrangian of a problem like the following: A particle is constrained to move along the a path defined by y = sin(x). Would you simply do this: x = x y = sin(x) x'^2 = x'^2 y'^2 = x'^2 (cos(x))^2...

Homework Statement Calculate the acceleration of the block B in the figure, assuming the surfaces and the pulleys ##P_1## and ##P_2## are all smooth and pulleys and string are light. (The mass of block C is m) Ans: F/(7m) Homework Equations The Attempt at a Solution I measured...

Homework Statement If acceleration of A is 2m/s2 to the left and acceleration of B is 1m/s2 to left, then acceleration of C is (see attachment 1) A)1m/s2 upwards B)1m/s2 downwards C)2m/s2 downwards D)2m/s2 upwards Ans: AHomework Equations The Attempt at a Solution (see attachment 2, I hope the...

Homework Statement See attached picture.Homework Equations The Attempt at a Solution I have the solution, but I'm puzzled by the first step in their solution, which reads Xa^(2) + Xb^(2) = L^(2) The solution provider then takes the time derivative of this expression which then produces...

could you please tell me how can the accelaration of masses m1 and m2 can be different. i am in a great necessity.so please explain me how can the two strings of the two sides of the lower pulley have different accelarations?

how to make the velocity of a pulley work in the constrained motion of a string? my inference is that how is the velocity of the pulley associated with the velocity of the string?

I've attached a screenshot of the question. This is what I've tried so far: I've calculated the initial energy of the system (which is all potential energy): Energy of disc: 0.5*I*w^2 + 0.5 *m*v^2 + m*g*h = 0 + 0 + 0 Energy of arm: 0.5*m*v^2 + m*g*h = 0 + 4*9.81*1.5Cos(45) = 41.62...