Q1: Suppose B=[0,1]x[0,2]x[0,3]x[0,4] in R4, and that C=[0,1]x[0,1]x[0,1]x[0,1]. Given that
∫ ∫ ∫ ∫f(x)=d4x=(2pi)4
B
What is the value of
∫ ∫ ∫ ∫ f(x1,2x2,3x3,4x4) d4x?
C[/color]
Solution:
Define x=G(u)=(u1,u2/2,u3/3,u4/4)
∫ ∫ ∫ ∫ f(x1,2x2,3x3,4x4) d4x
C
by change of variables...