In chemistry, a solution is a special type of homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a solvent. If the attractive forces between the solvent and solute particles are greater than the attractive forces holding the solute particles together, the solvent particles pull the solute particles apart and surround them. These surrounded solute particles then move away from the solid solute and out into the solution. The mixing process of a solution happens at a scale where the effects of chemical polarity are involved, resulting in interactions that are specific to solvation. The solution usually has the state of the solvent when the solvent is the larger fraction of the mixture, as is commonly the case. One important parameter of a solution is the concentration, which is a measure of the amount of solute in a given amount of solution or solvent. The term "aqueous solution" is used when one of the solvents is water.
I am a retired Tech who needs find better solutions for my everyday projects (my oldest book = CRC Handbook of Chemistry and Physics 52nd edition) . Presently - understanding heat transfer , water vapour mobility , air movement due to Temp and relative humidity. Too many variables , need help.
For a linear nth order differential equation with constant coefficients, the general solution can be expressed as a linear combination of n linearly independent solutions.
Fine...
By finding n linearly independent solutions, we are essentially covering all the necessary components to form the...
All simple harmonic motion must satisfy
$$\frac{d^2s}{dt^2}=-k^2s$$
for a positive value k.
The most well known solution is the sinusoidal one
$$ s=Acos/sin(\omega t + \delta)$$
A is amplitude, ##\omega##is related to frequency and ##\delta## is phase displacement.
My lecturer said that there...
For this,
I am trying to find solutions, however, I think I am getting a strange result that I am not too sure how to intercept.
I first multiply the first equation by 2 to get ##2x_1 - 8x_3 = 4## and then I add it to the second equation below to get ##0 = 1##. I think this means that there...