ashrafmod Thread starter Sep 17, 2006 #1 1\(5.6)+1\(5.6.7) + 1\(5.6.7.8)+..... 1\(5.6)+1\(5.6.7)+1\(5.6.7.8)+.....
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Sep 17, 2006 #2 Well, rewrite this as: [tex]\frac{1}{5*6}+\frac{1}{5*6*7}+\frac{1}{5*6*7*8}++++=\frac{4!}{6!}+\frac{4!}{7!}+\frac{4!}{8!}+++=4!*(\sum_{n=0}^{\infty}\frac{1}{n!})-4!*(\sum_{n=0}^{5}\frac{1}{n!})[/tex] see if you can get somthing out of this.
Well, rewrite this as: [tex]\frac{1}{5*6}+\frac{1}{5*6*7}+\frac{1}{5*6*7*8}++++=\frac{4!}{6!}+\frac{4!}{7!}+\frac{4!}{8!}+++=4!*(\sum_{n=0}^{\infty}\frac{1}{n!})-4!*(\sum_{n=0}^{5}\frac{1}{n!})[/tex] see if you can get somthing out of this.
AKG Science Advisor Homework Helper Messages 2,561 Reaction score 4 Sep 17, 2006 #3 Hint: [tex]e^x = \sum _{n=0} ^{\infty} \frac{x^n}{n!}[/tex]