# 1 pulley, 2 masses, 2 inclines

1. Mar 14, 2012

### TheronSimon

1. The problem statement, all variables and given/known data
Calculate the tension in the cable connecting the two masses. Assume all surfaces are frictionless.
in lieu of the picture here are the given specs:

on the left side a 5 kg mass with a 60' incline
on the right side a 6 kg mass with a 70'incline

2. Relevant equations
a=Fgsinθ
Fnet = ma

3. The attempt at a solution
my attempt was to calculate both sides for acceleration since its frictionless both would be non dependant on the weight of the mass
then i used
Fnet=ma
so Ft-Fg = ma
and after the math Ft = 41.45 and for the right side Ft= 114.66 but its the wrong answer so how do i complete this question?

2. Mar 14, 2012

### PhanthomJay

that is not true when you have diffferent inclines with the masses connected by a cable
you have to look at each mass separately using a free body diagram to identify the forces acting along the incline and apply Newton 2 to each mass separately
the tension force on each block is Ft directed along the incline and pulling away from the mass you are examining. But the gravity force along the incline is a component of Fg.
Note when you redo this problem that the tension in a cable wrapped around an ideal pulley is the same on both sides of the pulley.

3. Mar 17, 2012

### TheronSimon

Im still lost :S

4. Mar 17, 2012

### emailanmol

As mentioned by PhanthomJay,

the only analytical approach is to draw a Free Body Diagram(FBD) of both bodies and the string and identifying the constraints.

Guessing that the values shouldn't depend on mass, is risky and should be avoided at all costs.

When you draw the FBD of blocks, forces acting on them are their weight components parallel and perpendicular to incline.The normal reaction exerted by inclines and the tension force exerted by chord.

Now you draw the FBD of string which will help you corelate the tension forces exerted by strings on both bodies.(What is it? How does the mass of string affect this relation?)

Finally you identify the constraints.The only possible movement can be parallel to the inclined surfaces (body 1 will move parallel to incline 1, body 2 will move parallel to incline 2)and at all times no motion takes place perpendicular to the incline(body 1 has no motion perpendicular to incline 1 and body 2 has no motion perpendicular to incline 2).

Plug in the values.
Apply Netwons 2nd and Third Law relating action reaction forces.
What do you see?