2 * 10 ^ 20 charges move in a wire when we connect a 3.7 V battery. Ho

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SUMMARY

The discussion centers on calculating the total charge moved when a 3.7 V battery is connected to a wire with 2 × 1020 charge carriers. Each charge carrier, which is an electron, has a charge of 1.6 × 10−19 Coulombs. The total charge (Q) moved is calculated as Q = 2 × 1020 × 1.6 × 10−19 Coulombs, resulting in a total charge of 3.2 × 101 Coulombs. The work done by the battery is then determined using the formula W = Q × V.

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amizy9990
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Homework Statement
2 * 10 ^ 20 charges move in a wire when we connect a 3.7 V battery. How much work has the battery done?
Relevant Equations
W=Q*V
W=Q*V

2*10^20 Q * 3,7 V= 7,4*10^20 ??
 
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How much is the charge of one charge carrier ?
 
2*10^20
 
In what units ?
 
amizy9990 said:
2*10^20
No, there are 2 1020 charge carriers. What is the charge on ONE of them ?
 
the unit is Q
 
BvU said:
No, there are 2 1020 charge carriers. What is the charge on ONE of them ?
2Q?
 
what is Q ? How many of what units ?
 
  • #10
BvU said:
what is Q ? How many of what units ?
Q is charge. What do you mean?
 
  • #11
A bit of help. Look for electron's charge.
 
  • #12
Q is the symbol we use for charge. The SI unit for charge is the Coulomb.

In your exercise, the 2×1020 is the number of elementary charge carriers that were moved. Each of them carries 1.6×10−19 Coulomb, so the charge Q that was moved is 2×1020 times 1.6×10−19 Coulomb.
The work done is 3.7 V times Q
 
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  • #13
thanks, i forgot to calculate with electron's charge
 

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