2.7.3 AP calculus Exam Riemann sum

[karush]

View attachment 9364

ok basically t is 3 hours appart except between 7 and 12 of which I didn't know if we should intemperate.
other wise it is just adding up the 4 $(t)\cdot(R(t))$s.

 

[skeeter]

$\displaystyle 50 + \int_4^{15} R(t) \, dt \approx 50 + (3 \cdot 6.2 + 5 \cdot 5.9 + 3 \cdot 5.6) = 114.9 \text{ L}$

 

[karush]

$\displaystyle 50 + \int_4^{15} R(t) \, dt \approx 50 + (3 \cdot 6.2 + 5 \cdot 5.9 + 3 \cdot 5.6) = 114.9 \text{ L}$

ok, well I thot the intervals had to be equal but just take what is given here!

on your graph program is it possible just to show the ticks that apply?

 

[skeeter]

ok, well I thot the intervals had to be equal but just take what is given here!

on your graph program is it possible just to show the ticks that apply?

the intervals do not have to be equal ... what do you mean by "ticks that apply" ?

first base [4,7], height is R(7)

second base [7,12], height is R(12)

last base [12,15], height is R(15)