MHB 2.7.3 AP calculus Exam Riemann sum

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The discussion focuses on calculating a Riemann sum for a given function R(t) over specific intervals, emphasizing that the intervals do not need to be equal. Participants clarify the integration process, highlighting the importance of using the heights at the right endpoints for each interval. There is a query about whether a graphing program can display only relevant ticks, indicating a desire for clarity in visual representation. The calculations provided yield an approximate total of 114.9 liters when integrating R(t). Overall, the conversation centers on understanding Riemann sums and their application in the context of the AP Calculus exam.
karush
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ok basically t is 3 hours appart except between 7 and 12 of which I didn't know if we should intemperate.
other wise it is just adding up the 4 $(t)\cdot(R(t))$s.
 

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$\displaystyle 50 + \int_4^{15} R(t) \, dt \approx 50 + (3 \cdot 6.2 + 5 \cdot 5.9 + 3 \cdot 5.6) = 114.9 \text{ L}$
 

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skeeter said:
$\displaystyle 50 + \int_4^{15} R(t) \, dt \approx 50 + (3 \cdot 6.2 + 5 \cdot 5.9 + 3 \cdot 5.6) = 114.9 \text{ L}$

ok, well I thot the intervals had to be equal but just take what is given here!

on your graph program is it possible just to show the ticks that apply?
 
karush said:
ok, well I thot the intervals had to be equal but just take what is given here!

on your graph program is it possible just to show the ticks that apply?

the intervals do not have to be equal ... what do you mean by "ticks that apply" ?

first base [4,7], height is R(7)

second base [7,12], height is R(12)

last base [12,15], height is R(15)
 

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