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Yes, those are the correct equations.MaratZakirov said:Please prove your statement, it is totally not obvious to me.
But I agree that fewer claims is better, so let's write equations without it:
1. Momentum conservation parallel to sail (no friction with sail)
##m_p\vec{v}_{p \perp s} = m_p\vec{v}_{p \perp s}^1##
2. Momentum conservation along rail
##m_p\vec{v}_{p \parallel r} = m_p\vec{v}_{p \parallel r}^1 + m_c\vec{v}_c##
3. Restricton
##<\vec{v}_c, \vec{r}_{\perp}> = 0##
4. Energy conservation
##m_p\left| \vec{v}_p \right|^2 = m_p\left|\vec{v}_p^1\right|^2 + m_c\left|\vec{v}_c\right|^2##
Do you agree with these 4 euations?
In the square-on case, your equation 1 gives ##m_p\vec{v}_{p \perp s} = m_p\vec{v}_{p \perp s}^1=0##. I.e., it bounces back along the same line.