1. The problem statement, all variables and given/known data Block 1 with mass m1=4.04 kg rests on a very low friction horizontal ledge. This block is attached to a string that passes over a pulley, and the other end of the string is attached to the hanging block 2 of mass m2=2.02 kg, as shown. The pulley is a uniform disk of radius 11.85 cm and mass 1.980 kg. Calculate the speed of block 2 after it is released from rest and falls a distance of 1.84 m. What is the angular speed of the pulley at the instant when block 2 has fallen a distance of 1.84 m ? 2. Relevant equations Wtot=change in Energy KE=1/2 mv^2 W=integral of force*displacement N2L for rotation and translation 3. The attempt at a solution The tension of 2 and 1 on the pulley should be different but the accelerations of the blocks would be the same? a=m2*g/(mp/2 +m1+m2) T2=m2(g-a)=13.27 T1=m1*a=13.0829 WEm2=integral from 0 to 1.84 (T2xdx) = 22.47 J WT1m1=integral from 0 to 1.84 (T1xdx) = 22.1467 J work energy theorem: KE=W 1/2mv^2=WEm2+WT1m1 v=sqrt(2(WEm2+WT1m1)/mp)=3.33m/s This is not the correct answer, I'm not sure what I am doing wrong would the energy side of the equation be only kinetic?