2 dimensional collision with momentum

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SUMMARY

The discussion focuses on a two-dimensional collision problem involving two pucks with different masses, where Puck 1 is moving horizontally and Puck 2 is initially at rest. The conservation of momentum is applied in both the x and y dimensions, leading to the equations: m1(vf1*cos(θ1)) + m2(vf2*cos(θ2)) = m1(vix1) for the x-direction and m1(vf1*sin(θ1)) + m2(vf2*sin(θ2)) = 0 for the y-direction. The setup is correct, and the user is encouraged to proceed with solving for the final velocities using these equations.

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Homework Statement



There are 2 pucks with different masses. Puck 2 is initially at rest, and Puck 1 is moving horizontally in the positive x direction. The collision has sent the pucks off at angles θ1 and θ2 measured relative to the x-axis, along which Puck 1 initially traveled. Assume momentum is conserved for this collision and
write the conservation of momentum expression for each of the two dimensions.

Homework Equations





The Attempt at a Solution



I list out my variables.

mass
m1, m2

velocities
vix1
viy1=0

vfx1=vf1*cos(θ1)
vfy1=vf1*sin(θ1)

vix2=0
viy2=0

vfx2=vf2*cos(θ2)
vfy2=vf2*sin(θ2)

Here i set up the problem.

Pfsysx=Pisysx
m1(vf1*cos(θ1)) +m2(vf2*cos(θ2)) = m1(vix1)

Pfsysy=Pisysy
m1(vf1*sin(θ1)) +m2(vf2*sin(θ2)) = 0

does this seem right? can i go any further?
 
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