2 Finding length of curve problems

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Homework Help Overview

The discussion revolves around finding the length of curves defined by integrals, specifically focusing on two problems involving the integration of functions. The subject area includes calculus, particularly the concepts of arc length and parametric equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to apply the arc length formula and expresses confusion about substituting values into integrals. Some participants provide insights into the arc length formula and discuss the need for additional parametric equations for one of the problems.

Discussion Status

Participants are actively engaging with the problems, offering clarifications on the arc length formula and discussing the requirements for the integrals. There is acknowledgment of mistakes in the formula, and some guidance has been provided regarding the formatting of mathematical expressions.

Contextual Notes

The original poster indicates uncertainty about the setup of the problems and expresses difficulty with parametric equations. There is also mention of formatting issues related to typing mathematical symbols.

Sympathy
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1. Find the exact length of the curve analytically by antidifferentiation. You will need to simplify the integrand algebraically before finding an antiderivative.

y = the integral from -2 to x of the SQUARE ROOT (3t^4-1)dt, -2 < x < -1

note that the "<" is actually less than or equal to, don't know how to post that.

For this one, do I just plug the x in? x_x I'm really clueless on how to start

2. Find the length of the curve.

y = the integral of 0 to x of SQUARE ROOT (cos(2t))dt from x = 0 to x = pi/4The problem with me is I know how to do it in terms of y and x, but I am terrible at parametrics.

If you can, please help me with any of the above =) thanks
 
Last edited:
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Heres the arc length formula:

[tex]\int_a^b \sqrt{1+\frac{dy}{dx}} dx[/tex]. Sub in the requirements, easy enough to get.
 
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O sorry didnt actually read it through well. For the first one,

[tex]\int^{-2}_{x} \sqrt{3t^4 -1} dt[/tex]. If there wasn't an X there, but instead a normal number like you normally see, you would find the integral and then sub in b into it, and - the integral with a subbed in. In this case just sub in X.
 
For the second one, there should be a second parametric equation >.<
 
how do you actually type in the integral sign and stuff?
 
Here's one source:
http://www.artofproblemsolving.com/LaTeX/AoPS_L_GuideCommands.php
which will help with formatting the integrals

And another source for starters: (crash course in LaTeX at these forums:
https://www.physicsforums.com/misc/howtolatex.pdf
 
Last edited by a moderator:
Oh, and to see specifically how Gib Z did it, click to quote him, and take a look at what he has.

However, the formula has a small mistake in it...
(So, I copied and pasted from the quote so I could change it more simply)
[tex]\int_a^b \sqrt{1+(\frac{dy}{dx})^2} dx[/tex].
There's supposed to be a squared in there...
 
Yes, of course, drpizza's correct...I forget the squared, my bad :p
 
Btw, rather than actually having to quote me, just click on my latex pictures, that'll show up what I typed to show that code.
 

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