2 Identical Objects in Thermal Contact

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SUMMARY

When two identical objects with initial temperatures X and Y are placed in thermal contact, the final equilibrium temperature is T = (X + Y)/2, assuming no heat loss to the surroundings. This conclusion is derived from the law of conservation of energy, where the energy lost by one object equals the energy gained by the other. The proof utilizes the differential form of energy, expressed as dE = C_V dT, where E represents energy, C_V is heat capacity, and T is temperature. Integrating the energy equations confirms the final temperature formula.

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Master J
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If 2 identical objects with initial temperatures X and Y are placed together in thermal contact, then the final temperature is T= (X + Y)/2, X and Y actually being equal and excluding any heatloss to surroundings.

I understand this intuitively, but is there a precise mathematical proof? It's perhaps really simple, but the situation seems so straightforward to me I can't even think of a proof.
 
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The proof is based on law of conservation of energy (the energy lost by object X must be gained by object Y) and a way of writing energy in differential form, [itex]dE=C_V dT[/itex], where E is energy, CV is heat capacity, and T is temperature.

Putting these together, we have

[tex]dE_X=C_{V,X}dT_X=-C_{V,Y}dT_Y=-dE_Y[/itex]<br /> <br /> which can be integrated to give your original expression.[/tex]
 

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