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glover261

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- Thread starter glover261
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glover261

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- #2

Simon Bridge

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ie. did you try Newton's method of drawing free body diagrams for each mass?

- #3

glover261

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ie. did you try Newton's method of drawing free body diagrams for each mass?

Yeah I found the forces acting downwards but I think they are irrelevant because all the acceleration for the system would be in the sideways direction. I found that the acceleration of the 3kg (larger) mass is 15/3= 5ms/^2, but I'm not sure if this is correct because wouldn't the spring be pulling back on it and therefore lowering its acceleration? I am not really sure how to find the acceleration of the whole system, do I try find the acceleration of each mass and add them? How do I do that when a spring is involved?

- #4

Simon Bridge

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I think you may have left out some important information in your problem statement:Yeah I found the forces acting downwards but I think they are irrelevant because all the acceleration for the system would be in the sideways direction.

I was imagining both masses on a level frictionless surface with one to the left of the other ... in that situation the sum of the vertical (acting downwards) forces is zero.

This cannot follow from post #1 because you have not given any values for m1, m2 or F. It is unlikely to be correct because you have not accounted for the force from the spring.I found that the acceleration of the 3kg (larger) mass is 15/3= 5ms/^2,...

Yes....but I'm not sure if this is correct because wouldn't the spring be pulling back on it and therefore lowering its acceleration?

This is not how you would normally treat the accelerations of coupled masses is it?I am not really sure how to find the acceleration of the whole system, do I try find the acceleration of each mass and add them?

You include the force due to the spring in the free body diagram.How do I do that when a spring is involved?

Think how you would do this problem if the spring were replaced by a string?

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